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Lady_Fox [76]
3 years ago
8

After 8 examinations, Kacey's average was 55. Her next result increased her average to 60. What was the next score?

Mathematics
1 answer:
Yuki888 [10]3 years ago
5 0

Answer:

65

Step-by-step explanation:

they're going by 5s every time her score increases. hope I helped (:

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Please help i need to finish
elena-s [515]

Answer:

B. \overline A \overline C \cong \overline B \overline D

Step-by-step explanation:

The hypotenuse leg theorem (HL) requires the proof that the hypotenuse and the corresponding leg of the triangles to be equal in length. From the diagram, it can be found that \overline D \overline C is a common (shared) side of both triangles, so the additional fact needed is for the hypotenuses to be the same length.

∴ \overline A \overline C \cong \overline B \overline D is the additional fact needed to prove \triangle ADC \cong \triangle BCD

Hope this helps :)

5 0
3 years ago
What is the slope of the line that passes through the points (8,-4) and (6,3) in simplest form
Nesterboy [21]

Step-by-step explanation:

Rise of y-value = (-4) - (3) = -7.

Run of x-value = (8) - (6) = 2.

Slope of the line = Rise / Run = (-7) / (2) = -3.5.

5 0
3 years ago
Linda answered 19 questions correct out of 25 on her test. What percent of the test did Linda answer correctly? Explain your ans
TiliK225 [7]

Answer:

76%

Step-by-step explanation:

19/25÷100×100

7 0
2 years ago
Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
Urgent please help..
nlexa [21]
8.60 cm is the answer to your question and i used calculator.net for help
5 0
3 years ago
Read 2 more answers
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