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The same as has greater then less than plz anwser I am struggling

xeze [42]

For each power of ten , the number of zeros written in the product is the same as the number of exponents.

3 0

3 years ago

They intersect at the point (p, q). Which is greater, c or d? Explain how you know.

Natasha2012 [34]

Answer:

d is greater than c, since at $x = 0, g(x) > f(x)$

Step-by-step explanation:

We are given two exponential functions, f and g.

Since f has the higher base(3 instead of 2 in g), it increases faster, so initially, g is greater than f, and after point (p,q), f is greater than g.

The values of c and d are found when $x = 0$ . At this point, we have that g is greater than f, so d is greater than c.

4 0

3 years ago

I need help w/ this!! thank you

Fittoniya [83]

<h3>Answer:</h3>

$\boxed{\pink{\sf \leadsto Yes \ there \ is \ a \ solution \ of \ the \ given \ inequality .}}$

<h3>Step-by-step explanation:</h3>

A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.

The inequality given to us is :-

$\bf\implies |2y + 3 | - 1 \leq 0 \\\\\bf\implies |2y+3|\leq 1 \\\\\bf\implies (|2y+3|)^2 \leq 1^2 \\\\\bf\implies (2y+3)^2 \leq 1 \\\\\bf\implies (2y)^2+3^2+2(2y)(3) \leq 1 \\\\\bf\implies 4y^2+9+12y - 1 \leq 0 \\\\\bf\implies 4y^2+12y+8 \leq 0 \\\\\bf\implies 4( y^2 + 3y + 2 ) \leq 0 \\\\\bf\implies y^2+3y +2 \leq 0 \:\:\bigg\lgroup \purple{\bf Standard \ form \ of \ inequality }\bigg\rgroup \\\\\bf\implies y^2y+2y+y+2 \leq 0 \\\\\bf\implies y(y+2)+1(y+2)\leq 0 \\\\\bf\implies ( y+2)(y+1)\leq 0 \\\\\bf\implies \boxed{\red{\bf y \leq (-2) , (-1) }}$