Answer:
(2,7) is not a solution to the given system of equations.
Step-by-step explanation:
Given system of equation is:
2x + 3 = y
2x + y = 15
To check whether (2,7) is solution to this system or not, we will put x=2 and y=7 in both equations.
Putting x=2 and y=7 in Eqn 1
2(2) + 3 = 7
4 + 3 = 7
7 = 7
Thus the ordered pair satisfies the equation
Putting x=2 and y=7 in Eqn 2
2(2) + 7 = 15
4 + 7 = 15
11 ≠ 15
The ordered pair do not satisfy the second equation.
Hence,
(2,7) is not a solution to the given system of equations.
Answer:
3x^2 + 12x + 4y^2 - 8y = 32
Step-by-step explanation:
3(x^2+4x)+4(y^2-2y)=32
At first we have to break the parenthesis to get the variables in normal position. To break those, we have to multiply each with the help of algebraic expression:
or, (3*x^2) + (3 × 4x) + (4 × y^2) - (4 × 2y) = 32
or, 3x^2 + 12x + 4y^2 - 8y = 32
Since the equation does not have anything to add or deduct, therefore, it is the answer.
4. 14-6w
6. 12h-14
8. 22a+10b
In solution it wil be
4. (9+5)-6w
6. (5h+7h) - (6+8)
8. (26a-4a) + (2b+10b)
Answer:
x=-7
Step-by-step explanation:
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