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3 years ago

6

Read the hypothesis below. Hypothesis: if a steel surface is wet with water, then the friction will be reduced, which question b

est matches the hypothesis ???

1 answer:

Anna71 [15]3 years ago

6 0

Answer:

how will water affect the force of friction

90% sure

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How many sex chromosomes do females have

MaRussiya [10]

Hello there!

Your answer is going to be 2. Females have two x chromosomes, while males have two as well, but males have an x and a y.

Hope this helps you! Feel free to ask for help anytime!

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3 years ago

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It is January. The temperature is 33°F, and the wind is blowing. Huge clouds are coming in from the west.

Dimas [21]

Answer:

Explanation:

Since the atmosphere is fixed to the earth by gravity and rotates with the earth, there would be no circulation if some force did not upset the atmosphere's equilibrium. The heating of the earth's surface by the sun is the force responsible for creating the circulation that does exist.

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Calcium hydroxide is titrated with nitric acid. What volume of 0.0200 M calcium hydroxide is required to neutralize 35.00 ml of

gogolik [260]

Answer:

43.75 ml

Explanation:

Given that the equation of the reaction is;

2HNO3(aq) + Ca(OH)2(aq) ---> Ca(NO3)2(aq) + 2 H20(l)

Concentration of acid CA= 0.05 M

Concentration of base CB = 0.02 M

Volume of acid VA = 35.00ml

Volume of base VB= ???

Number of moles of acid NA= 2

Number of moles of base NB=1

From

CAVA/CBVB= NA/NB

Making VB the subject of the formula;

VB= CAVANB/CBNA

VB= 0.05 × 35 × 1/ 0.02 × 2

VB=1.75 /0.04

VB= 43.75 ml

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3 years ago

Which of the following is an oxidation-reduction reaction? a. HCl(aq) + LiOH(aq) → LiCl(aq) + H2O(l) b. Pb(C2H3O2)2(aq) + 2 NaCl

saw5 [17]

Answer: Option (d) is the correct answer.

Explanation:

A reaction in which there occurs change in oxidation state of reacting species is known as an oxidation-reduction reaction.

(a) $HCl(aq) + LiOH(aq) \rightarrow LiCl(aq) + H_{2}O(l)$

Will be written as:

$H^{+} + Cl^{-} + Li^{+} + OH^{-} \rightarrow Li^{+} + Cl^{-} + H^{+} + OH^{-}$

In this reaction, there occurs no change in oxidation state of reacting species. Hence, it is not an oxidation-reduction reaction.

(b) $Pb(C_{2}H_{3}O_{2})_{2}(aq) + 2NaCl(aq) \rightarrow PbCl_{2}(s) + 2 NaC_{2}H_{3}O_{2}(aq)$

Will be written as:

$Pb^{2+} + 2C_{2}H_{3}OO^{-} + 2Na^{+} + 2Cl^{-} \rightarrow Pb^{2+} + 2Cl^{-} + 2Na^{+} + 2C2H3OO^{-}$

Similarly here, there occurs no change in oxidation state of reacting species. Hence, it is not an oxidation-reduction reaction.

(c) $NaI(aq) + AgNO_{3}(aq) \rightarrow AgI(s) + NaNO_{3}(aq)$

Will be written as:

$Na^{+} + I^{-} + Ag^{2+} + NO^{2-}_{3} \rightarrow AgI(s) + Na^{+} + NO^{2-}_{3}(aq)$

Here, also there occurs no change in oxidation state of reacting species. Hence, it is not an oxidation-reduction reaction.

(d) $Mg(s) + 2 HCl(aq) \rightarrow MgCl_{2}(aq) + H_{2}(g)$

So, here there occurs change in oxidation state of Mg from 0 to +2 and oxidation state of H changes from +1 to 0. Hence, it is an oxidation-reduction reaction.

Thus, we can conclude that $Mg(s) + 2 HCl(aq) \rightarrow MgCl_{2}(aq) + H_{2}(g)$ is an oxidation-reduction reaction.

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3 years ago

The component of solution present in smaller quantity is called

vampirchik [111]

Answer:
A solute

Explanation:

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