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yawa3891 [41]
3 years ago
11

Which of the following is an example of erosion under the force of gravity?

Chemistry
1 answer:
taurus [48]3 years ago
4 0

the answer i believe is b:saltation, which is a form of wind erosion

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Five hundred (500) milliliters of sodium chloride 0.9% is prescribed to be given over 4 hours using a volumetric pump. What's th
Angelina_Jolie [31]

<u>Given:</u>

Volume of 0.9% NaCl = 500 ml

Time (t) = 4 hrs

<u>To determine:</u>

The infusion rate of NaCl in ml/hr

<u>Explanation:</u>

Based on the information- 500 ml of NaCl is to be given over a time span of 4 hrs

Hence, the volume of NaCl to be administered per hr is:-

= 1 hr * 500 ml/4 hr = 125 ml

Ans: Infusion rate = 125 ml/hr

6 0
3 years ago
2. Why do ions form?
noname [10]

Answer:

When atoms lose or gain electrons, they become positively or negatively charged ions. In an ionic compound, the ions are arranged in a three-dimensional structure called a crystal. ... When an atoms gains or loses electrons, it gains a charge, thus becoming an ion.

Explanation:

7 0
2 years ago
Read 2 more answers
What is the molecular geometry if you have 3 single bonds and 1 lone pair around the central atom?
Elodia [21]

Answer:

There are 2 double bond units and 1 lone pair, which will try to get as far apart as possible - taking up a trigonal planar arrangement. Because the lone pair isn't counted when you describe the shape, SO2 is described as bent or V-shaped.

Explanation:

There are 2 double bond units and 1 lone pair, which will try to get as far apart as possible - taking up a trigonal planar arrangement. Because the lone pair isn't counted when you describe the shape, SO2 is described as bent or V-shaped.

7 0
3 years ago
The bomb that destroyed tje Murrah Federal Office Building in Oklahoma City in April 1995 was constructed from ordinary material
Leto [7]

Answer:

ΔH⁰(11.4g NH₄NO₃) = -30.59Kj (4 sig. figs. ~mass of  NH₄NO₃(s) given) (exothermic)

Explanation:

           3NH₄NO₃(s) + C₁₀H₂₂(l) + 14O₂(g) => 3N₂(g)  +  17H₂O(g)   +  10CO₂(g)

ΔH⁰(f):  3(-365.6)Kj     1(-301)Kj    14(0)Kj       3(0)Kj    17(-241.8)Kj    10(-393.5)Kj

            = -1096.8Kj     = -301Kj     = 0Kj         = 0Kj      = -4110.6Kj    = -3930.5Kj

ΔHₙ°(rxn) = ∑ (ΔH˚(f)products) - ∑(ΔH˚(f)reactants)

= [3(0)Kj + 17(-241.8)Kj + (-393.5)Kj] - [(-(1096.8)Kj + (-301)Kj + (0)Kj]

= [-(8041.1) - (-1397.8)]Kj

= -6643.3Kj (for 3 moles NH₄NO₃ used in above equation)  

∴ Standard Heat of Rxn = -6643.3Kj/3moles = -214.8Kj/mole NH₄NO₃(s)

ΔH°(rxn for 14.11g  NH₄NO₃(s)) = (11.4g/80.04g·mol⁻¹)(-214.8Kj/mol) = 30.5937Kj ≅ 30.59Kj (4 sig. figs. ~mass of  NH₄NO₃(s) given)

5 0
3 years ago
A. 1
Lubov Fominskaja [6]
I think it’s B. I’m not 100% sure but I believe it is B! Srry if this is late btw.
8 0
2 years ago
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