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2 years ago

Find the requested values. 45° 5c+5°

Mathematics

1 answer:

Amanda [17]2 years ago

3 0

Answer:

c = 8

Step-by-step explanation:

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Angle a=126°. What is the measure of angle b? Explain how you calculated your answer.

velikii [3]

It’s 57 57 57 okay i had this question once

7 0

2 years ago

A box of oatmeal must contain 16 oz. The machine that fills the oatmeal boxes is set so that, on the average, a box contains 16.

Vadim26 [7]

Answer:

29. 15.87%

30. 4.75%

31. 0.62%

32. probability cannot be calculated (0%)

Step-by-step explanation:

We have that the formula of the normal distribution is:

z = (x - m) / sd

where x is the value we are going to evaluate, m is the mean and sd is the standard deviation

x = 16 and m = 16.5

when sd = 0.5

z = (16 - 16.5) /0.5

z = -1

Now when looking in the z table, we have that the corresponding value is 0.1587, that is, the probability is 15.87%

when sd = 0.3

z = (16 - 16.5) /0.3

z = -1.67

Now when looking in the z table, we have that the corresponding value is 0.0475, that is, the probability is 4.75%

when sd = 0.2

z = (16 - 16.5) /0.2

z = -2.5

Now when looking in the z table, we have that the corresponding value is 0.0062, that is, the probability is 0.62%

when sd = 0

z = (16 - 16.5) / 0

z = infinity

probability cannot be calculated

4 0

2 years ago

Divide the whole into pieces that are each ⅙ of the whole. Then, solve the equation.

yKpoI14uk [10]

Answer: 6

Explanation

If we divide our figure into six, we get the following figure:

As we can see, we are left with 6 equal parts. This can be confirmed by solving the equation:

$1\div\frac{1}{6}=\frac{6}{1}=6$

6 0

9 months ago

Whats a quadrilateral

Karolina [17]

A four sided polygon, 4 edges and 4 corners

4 0

2 years ago

Read 2 more answers

Remember to show work and explain. Use the math font.

MrMuchimi

Answer:

$\large\boxed{1.\ f^{-1}(x)=4\log(x\sqrt[4]2)}\\\\\boxed{2.\ f^{-1}(x)=\log(x^5+5)}\\\\\boxed{3.\ f^{-1}(x)=\sqrt{4^{x-1}}}$

Step-by-step explanation:

$\log_ab=c\iff a^c=b\\\\n\log_ab=\log_ab^n\\\\a^{\log_ab}=b\\\\\log_aa^n=n\\\\\log_{10}a=\log a\\=============================$

$1.\\y=\left(\dfrac{5^x}{2}\right)^\frac{1}{4}\\\\\text{Exchange x and y. Solve for y:}\\\\\left(\dfrac{5^y}{2}\right)^\frac{1}{4}=x\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\dfrac{(5^y)^\frac{1}{4}}{2^\frac{1}{4}}=x\qquad\text{multiply both sides by }\ 2^\frac{1}{4}\\\\\left(5^y\right)^\frac{1}{4}=2^\frac{1}{4}x\qquad\text{use}\ (a^n)^m=a^{nm}\\\\5^{\frac{1}{4}y}=2^\frac{1}{4}x\qquad\log_5\ \text{of both sides}$

$\log_55^{\frac{1}{4}y}=\log_5\left(2^\frac{1}{4}x\right)\qquad\text{use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\\dfrac{1}{4}y=\log(x\sqrt[4]2)\qquad\text{multiply both sides by 4}\\\\y=4\log(x\sqrt[4]2)$

$--------------------------\\2.\\y=(10^x-5)^\frac{1}{5}\\\\\text{Exchange x and y. Solve for y:}\\\\(10^y-5)^\frac{1}{5}=x\qquad\text{5 power of both sides}\\\\\bigg[(10^y-5)^\frac{1}{5}\bigg]^5=x^5\qquad\text{use}\ (a^n)^m=a^{nm}\\\\(10^y-5)^{\frac{1}{5}\cdot5}=x^5\\\\10^y-5=x^5\qquad\text{add 5 to both sides}\\\\10^y=x^5+5\qquad\log\ \text{of both sides}\\\\\log10^y=\log(x^5+5)\Rightarrow y=\log(x^5+5)$

$--------------------------\\3.\\y=\log_4(4x^2)\\\\\text{Exchange x and y. Solve for y:}\\\\\log_4(4y^2)=x\Rightarrow4^{\log_4(4y^2)}=4^x\\\\4y^2=4^x\qquad\text{divide both sides by 4}\\\\y^2=\dfrac{4^x}{4}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\y^2=4^{x-1}\Rightarrow y=\sqrt{4^{x-1}}$

6 0

2 years ago