what is the length of the hypotenuse of a right triangle whose legs are 5 and the square root of two
1 answer:
To begin with, you need to use Pythagorean Theorem (a^2+b^2=c^2)
5 becomes 25
Solve for the square root first which is 1.414213562 and this becomes 2
So you add this two numbers and it will give you 27
Square root 27 and its 5.196152423
You can check it using this equation
5^2+square root of 2^2=5.196152423^2
The length of the hypotenuse is 5.1961524227066
~Revilla03
5 becomes 25
Solve for the square root first which is 1.414213562 and this becomes 2
So you add this two numbers and it will give you 27
Square root 27 and its 5.196152423
You can check it using this equation
5^2+square root of 2^2=5.196152423^2
The length of the hypotenuse is 5.1961524227066
~Revilla03
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Most of the square numbers are even.so if we need to find root over we need an even number to convert it to perfect square.
See the example below
- P=3
- B=4
- H=5
Some other triplets are
- (6,8,10)
- (5,12,13)
- (8,15,17)