what is the length of the hypotenuse of a right triangle whose legs are 5 and the square root of two
1 answer:
To begin with, you need to use Pythagorean Theorem (a^2+b^2=c^2)
5 becomes 25
Solve for the square root first which is 1.414213562 and this becomes 2
So you add this two numbers and it will give you 27
Square root 27 and its 5.196152423
You can check it using this equation
5^2+square root of 2^2=5.196152423^2
The length of the hypotenuse is 5.1961524227066
~Revilla03
5 becomes 25
Solve for the square root first which is 1.414213562 and this becomes 2
So you add this two numbers and it will give you 27
Square root 27 and its 5.196152423
You can check it using this equation
5^2+square root of 2^2=5.196152423^2
The length of the hypotenuse is 5.1961524227066
~Revilla03
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Answer:
21.62m
Step-by-step explanation:
first draw the the pipe
second you need know wich is the angle between the pipe and the corner
β=Tan^-1(6/9)=33.7
find the components using tow triangles
a=9/cos(33.7)=10.81m
b=6/sen(33.7)=10.81m
finally sum the leghts
L=10.81+10.81=21.62mm
attached procedure
