what is the length of the hypotenuse of a right triangle whose legs are 5 and the square root of two
1 answer:
To begin with, you need to use Pythagorean Theorem (a^2+b^2=c^2)
5 becomes 25
Solve for the square root first which is 1.414213562 and this becomes 2
So you add this two numbers and it will give you 27
Square root 27 and its 5.196152423
You can check it using this equation
5^2+square root of 2^2=5.196152423^2
The length of the hypotenuse is 5.1961524227066
~Revilla03
5 becomes 25
Solve for the square root first which is 1.414213562 and this becomes 2
So you add this two numbers and it will give you 27
Square root 27 and its 5.196152423
You can check it using this equation
5^2+square root of 2^2=5.196152423^2
The length of the hypotenuse is 5.1961524227066
~Revilla03
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ANSWER
Option D is correct
EXPLANATION
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Also the second is resolved to obtain,
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The correct answer is D.
Answer:
The area of a regular octagon with a perimeter of 80 ft and an apothem of 12.07 feet is 482.8 ft².
Step-by-step explanation:
An octagon is a polygon with eight sides. An octagon is regular (also called a regular octagon) is a polygon with all eight sides equal.
The apothem of a regular octagon is the shortest distance between the center and any of its sides, in other words, it is the distance that separates the center of the polygon from the central point of each side of the octagon.
The area is calculated using the following formula:
Where:
- n is the number of sides.
- L is the length of one of the sides.
- Ap is the value of the apothem.
Being n = 8 being an octagon and the perimeter P the sum of the sides of the octagon (P = 8 * L), the area of the regular octagon can be calculated by:
In this case:
- P=80 ft
- Ap=12.07 ft
Replacing:
Solving:
Area=482.8 ft²
<u><em>The area of a regular octagon with a perimeter of 80 ft and an apothem of 12.07 feet is 482.8 ft².</em></u>