what is the length of the hypotenuse of a right triangle whose legs are 5 and the square root of two
1 answer:
To begin with, you need to use Pythagorean Theorem (a^2+b^2=c^2)
5 becomes 25
Solve for the square root first which is 1.414213562 and this becomes 2
So you add this two numbers and it will give you 27
Square root 27 and its 5.196152423
You can check it using this equation
5^2+square root of 2^2=5.196152423^2
The length of the hypotenuse is 5.1961524227066
~Revilla03
5 becomes 25
Solve for the square root first which is 1.414213562 and this becomes 2
So you add this two numbers and it will give you 27
Square root 27 and its 5.196152423
You can check it using this equation
5^2+square root of 2^2=5.196152423^2
The length of the hypotenuse is 5.1961524227066
~Revilla03
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Explanation:
Conversion of a quadratic equation from standard form to vertex form is done by completing the square method.
Assume the quadratic equation to be where x is the variable.
Completing the square method is as follows:
- send the constant term to other side of equal
- divide the whole equation be coefficient of
, this will give
- add
to both side of equality
- Make one fraction on the right side and compress the expression on the left side
- rearrange the terms will give the vertex form of standard quadratic equation
Follow the above procedure will give the vertex form.
(NOTE : you must know that . Use this equation in transforming the equation from step 3 to step 4)