Answer:
Option b seems to be the correct approach.
Explanation:
- Liaison seems to be collaboration as well as the communication of knowledge among various organizations as well as between multiple portions of the institution.
- Communication among groups of the military services or indeed any entity shall be established in needed to guarantee coordinated action, partnership, respectively.
Some other options aren't relevant to the current situation in question. So choice b was its right one
Answer: a. Boot camp is the military's version of employee orientation.
Explanation:
To become an employee in a company, it is standard practice for the employer to give the employee an orientation so that they may be able to perform better at their jobs because they would know what is expected of them and how to go about achieving this.
This is the same for the military. When they send recruits to boot camps, they are doing their version of employee orientation because the recruit will learn what Uncle Sam expects from them and how they are to accomplish these tasks.
Answer:
Conversion Cost Equivalent units FIFO 39, 125
Explanation:
Beginning WIP 5,000 30% completed
transferred units 39,500
ending WIP 4,500 25% completed
<u>The equivalent units will be:</u>
the transferred units
- complete portion for the beginning WIP
+ complete portion of the ending WIP
transferred out 39,500
work in previous period
5,000 x 30% = (1,500)
worked but not complete
4,500 x 25% = <u> 1, 125 </u>
Equivalent units FIFO 39, 125
Answer:
Sample size is 16
Mean 4
Standard deviation of the sample is 0.3.
Explanation
The Central Limit Theorem estabilishes that, for a random variable X, with mean 
and standard deviation 
, a large sample size can be approximated to a normal distribution with mean and standard deviation 
.
In this problem, we have that:
The population has a mean of four hours, with a standard deviation of 1.2 hours. The sample is the 16 of the employees.
So
The sample size is 16, so 
The mean of the sample is the same as the population mean, so 
.
The standard deviation of the sample is 
