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matrenka [14]
2 years ago
11

Sin230° = _____ -sin50° sin50° sin130°

Mathematics
1 answer:
likoan [24]2 years ago
8 0
Sin230=sin(180+50)=sin180cos50+cos180sin50=-sin50 answer 1
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A practice problem regarding quadrilateral
Vlad [161]
Okay, I’m pretty sire this is right.
A: (-1, 3)
B: (-3, 2)
C: (-8, 3)
D: (-4, 3)

To do this problem (I am not completely confident in this) I am pretty sure you flip the signs for both the x and y values due to the rotation of the shape 180°, then add 6 to the y value.
3 0
2 years ago
Jim is saving nickels, dimes and quarters to buy a baseball mitt. He has 12 more
Harrizon [31]

Answer:

36 quarters   48 dimes  64 nickels

Step-by-step explanation:

quarter = q

dime = q+12

nickel = 2q-8

$17 = 1,700 cents

(q)25 + (q+12)10 + (2q-8)5 = 1,700

25q +10q+120  +10q-40 =1,700

45q+80 = 1,700

45q = 1620

q= 36      

 36     QUARTERS x25 =  900cents

 48 DIMES    x10      =         480 cents

  64 NICKELS x 5 =             320 cents

  TOTAL                              1,700 cents ($17)

5 0
2 years ago
Can someone help me learn linear equations​
Bezzdna [24]

Answer:

Linear equations that go in a straight line.

They are linear so they don’t curve like parabolas.

Step-by-step explanation:

See this picture. It will definitely help you!

6 0
3 years ago
99.73-63.434 rounded to the nearest whole number
Bingel [31]
<span>99.73-63.434 = 
</span>36.296
Round this to the nearest whole number 
= 36
6 0
2 years ago
A rectangle is transformed according to the rule r0, 90º. the image of the rectangle has vertices located at r'(–4, 4), s'(–4, 1
Korvikt [17]

Answer:

Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

Counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Step-by-step explanation:

Given  : rectangle has vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4)

To find :  transformed according to the rule 90º , what is the location of q?

Solution : we have given that

vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4).

By the rule of 90º rotation clock wise rule : (x ,y ) →→ ( y , -x )

90º rotation counter clock wise rule : (x ,y ) →→ ( -y , x ).

Then   Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Therefore, Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

4 0
3 years ago
Read 2 more answers
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