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notsponge [240]
3 years ago
10

If you were going to apply statistical methods to analyze teacher evaluations, which question form, A or B, would be better? For

m A: In your own words, tell how this teacher compares with other teachers you have had. Form B: Use the following scale to rank your teacher as compared with other teachers you have had.a. Form B would be better because statistical methods can be applied to the ordinal data. b. Form B would be better because statistical methods can be applied to the nominal data. c. Form A would be better because statistical methods can be applied to the nominal data. e. Form A would be better because statistical methods can be applied to the ordinal data.
Mathematics
1 answer:
Goshia [24]3 years ago
5 0

Answer:

a. Form B would be better because statistical methods can be applied to the ordinal data.

Step-by-step explanation:

Ordinal data can be ranked. This teacher evaluation can be ranked on a scale of 1-10 for example. Ordinal data can  provide good information about the choice of the person who is responding. And these informations are quantitative in nature.

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Bonnie earns $455 a week, and she works 5 days a week. what is her daily wage?
Nostrana [21]
91$ per day you divid 455$ by the 5 days and get 91$
5 0
3 years ago
there are 6 twenty pound boxes and 8 sixty pound boxes of produce on a truck. how many pounds of produce are on the truck
Klio2033 [76]

6 *20 = 120

8 *60 = 480


120 + 480 = 600 pounds total

6 0
3 years ago
11. Let f(x) = 2x² + 7x + 5
Lady_Fox [76]

Answer:

(x+1)(2x+5)

Step-by-step explanation:

f(x) = 2x² + 7x + 5

Factor the expression by grouping. First, the expression needs to be rewritten as 2x²+ax+bx+5. To find a and b, set up a system to be solved.

a+b=7

ab=2×5=10

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 10.

1,10

2,5

Calculate the sum for each pair.

1+10=11

2+5=7

The solution is the pair that gives sum 7.

a=2

b=5

2x²+7x+5 as (2x²+2x)+(5x+5).

(2x²+2x)+(5x+5)

Factor out 2x in the first and 5 in the second group.

2x(x+1)+5(x+1)

Factor out common term x+1 by using distributive property.

(x+1)(2x+5)

7 0
2 years ago
Please help me if you can thank you.
Anarel [89]
X could be 1.5
.........
5 0
3 years ago
Read 2 more answers
If g (x) = 1/x^2 then g (x+h) - g (x)/h
nignag [31]

\bf g(x)=\cfrac{1}{x^2}~\hspace{5em}\cfrac{g(x+h)-g(x)}{h}\implies \cfrac{\frac{1}{(x+h)^2}-\frac{1}{x^2}}{h} \\\\\\ \textit{using the LCD of }(x+h)^2(x^2)\qquad \cfrac{\frac{x^2-(x+h)^2}{(x+h)^2(x^2)}}{h}\implies \cfrac{x^2-(x+h)^2}{h(x+h)^2(x^2)} \\\\\\ \cfrac{x^2-(x^2+2xh+h^2)}{h(x+h)^2(x^2)}\implies \cfrac{\underline{x^2-x^2}-2xh-h^2}{h(x+h)^2(x^2)}\implies \cfrac{-2xh-h^2}{h(x+h)^2(x^2)}


\bf \cfrac{\underline{h}(-2x-h)}{\underline{h}(x+h)^2(x^2)}\implies \cfrac{-2x-h}{(x+h)^2(x^2)}\implies \cfrac{-2x-h}{(x^2+2xh+h^2)(x^2)} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \cfrac{-2x-h}{x^4+2x^3h+x^2h^2}~\hfill

4 0
3 years ago
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