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3 years ago

Suppose T= {-8,-4,0,4,8,12,16,20} and K= {-3,-2,-1,0,1,2,3,4,5,6}. What is T U K?

Mathematics

1 answer:

Ivanshal [37]3 years ago

3 0

T U K = { -8,-4, -3, -2, -1, 0, 1,2,3,4, 5,6,8,12,16,20}

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Angle BCD is a circumscribed angle of circle A. Angle BAC measures 53°.

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Answer:

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Step-by-step explanation:

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3 years ago

Perpendicular and Angle bisectors

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The answer is 8, because CA and BC are equal

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3 years ago

Don't answer if you don't know

SIZIF [17.4K]

0.10d + 0.25q = 3.55
q = d + 3

0.10d + 0.25(d + 3) = 3.55
0.10d + 0.25d + 0.75 = 3.55
0.10d + 0.25d = 3.55 - 0.75
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d = 2.80/0.35
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3 years ago

I am greater than 4 tens and less than 5 tens I have 9 ones

aliina [53]

4 tens = 40 and 5 tens = 50 … therefore the number has to be between 40 and 50

So: 40 < x <50 … this says that x is greater than 40 and less than 50

So the possible numbers would be: 41,42,43,44,45,46,47,48,49

Now the number must have 9 ones … which mean the only number would be 49

4 0

3 years ago

Use completing the square to determine which of the following gives the solutions to 3x2 - 24x + 40 = 28.

jeka94

Answer:

$x=4+2\sqrt{3}$

$x=4-2\sqrt{3}$

Step-by-step explanation:

<u>Completing the square</u>

when $ax^2+bx+c=0$

Given equation:

$3x^2-24x+40=28$

Subtract 40 from both sides:

$\implies 3x^2-24x=-12$

Divide both sides by 3:

$\implies x^2-8x=-4$

Add the square of half the coefficient of $x$ to both sides:

$(\frac{b}{2})^2=(\frac{-8}{2})^2=16$

$\implies x^2-8x+16=-4+16$

Factor the left side and simplify the right side:

$\implies (x-4)^2=12$

Square root both sides:

$\implies x-4=\pm\sqrt{12}$

Add 4 to both sides and simplify the radical:

$\implies x=4\pm\sqrt{4 \cdot 3}$

$\implies x=4\pm\sqrt{4}\sqrt{3}$

$\implies x=4\pm2\sqrt{3}$

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2 years ago