Suppose T= {-8,-4,0,4,8,12,16,20} and K= {-3,-2,-1,0,1,2,3,4,5,6}. What is T U K?

Mathematics

1 answer:

Ivanshal [37]2 years ago

3 0

T U K = { -8,-4, -3, -2, -1, 0, 1,2,3,4, 5,6,8,12,16,20}

You might be interested in

Please help

Lapatulllka [165]

I think it’s A.6.3
Sorry if I’m wrong but I’m pretty sure it’s that.

7 0

3 years ago

the 41st term of the arithmetic sequence is -539 and the 54th term is -708. Find the value of the 80th term

yulyashka [42]

Answer:

$a _{n} = a _{1} + (n - 1)d \\ a _{41} = - 534 \\ a _{54} = - 708 \\ a _{41} = a _{1} + (41 - 1)d = - 534 \\ a _{1} + 40d = - 534 \: \: ...(1)\\ a _{54} = a _{1} + (54 - 1)d =- 708 \\ a _{1} + 53d = - 708 \: \: ...(2)$

Try to solve the similtanious equation to find the first term and the common difference, then use that information to figure out the 80th term... Update me if you need further help ...

7 0

2 years ago

A survey of 1 comma 558 randomly selected adults showed that 522 of them have heard of a new electronic reader. The accompanying

sineoko [7]

Answer with explanation:

Let p be the proportion of adults have heard of the new electronic reader.

Given claim : The accompanying technology display results from a test of the claim that 38% of adults have heard of the new electronic reader.

i.e. $p=0.38$

Then , the set of hypothesis will be :-

$H_0: p=0.38\\\\H_a:p\neq0.38$

Since, the alternative hypothesis is two tailed , so the test is two-tailed test.

Also, it is given that the sample size : $n=1558$

Number of adults showed that they have heard of a new electronic reader=522

So the sample proportion for adults have heard of the new electronic reader : $\hat{p}=\dfrac{522}{1558}\approx0.34$

The test statistic for proportion is given by :-

$z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\\\\Rightarrow\ z=\dfrac{0.34-0.38}{\sqrt{\dfrac{0.38(1-0.38)}{1558}}}\\\\\\\Rightarrow\ z=-3.25279036541\approx-3.25$