Answer:
a) 16.25 centimeters
b) 6.8 centimeters
Step-by-step explanation:
We can set up a proportion for both of these problems.
a) Look at the longest side of each triangle. We can set up a fraction: 7.2/18. We can also set up a fraction for XZ and PR:
6.5/x
x represents the length you're trying to find.
Since the triangles are similar, we have an equation:
7.2/18=6.5/x
Cross multiply
16.25
XZ is 16.25 centimeters long.
b)
We can do same thing:
7.2/18=x/17
Cross multiply
6.8
QR is 6.8 centimeters long.
Hope this helps!
Answer:
A=2(1+2)a2=2·(1+2)·22≈19.31371
Step-by-step explanation:
hope this helps!
R = sqrt 3 * (V /( pi * h))
V = 62.8
pi = 3.14
h = 15
now we sub
R = sqrt 3 * (62.8 / (3.14 * 15)
R = sqrt 3 * (62.6 / 47.1)
R = sqrt 3 * 1.33
R = sqrt 3.99
R = 1.9 rounds to 2 inches <===
Answer:
1,224 feet
Step-by-step explanation:
Multiply 51 feet times 24 feet and then you get 1,224 ft.
Using the recursion equation, it is found that the value of the 2nd iterate is:

<h3>What is the recursive equation?</h3>
The value of the nth iteration is given by:

The initial estimate is:

Hence, the 1st iterate is given by:

The 2nd iterate is:

Thus, the fourth option is correct.
You can learn more about recursive equations at brainly.com/question/6561461