Answer:

Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 40 dollars
Standard Deviation, σ = 7 dollars
Sample size,n = 51
We are given that the distribution of cost of shrimp is a bell shaped distribution that is a normal distribution.
Formula:

Standard error due to sampling =

P(sample mean would differ by true mean by more than 0.6)



0.5404 is the required probability.
The smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.
What is the intermediate value theorem?
Intermediate value theorem is theorem about all possible y-value in between two known y-value.
x-intercepts
-x^2 + x + 2 = 0
x^2 - x - 2 = 0
(x + 1)(x - 2) = 0
x = -1, x = 2
y intercepts
f(0) = -x^2 + x + 2
f(0) = -0^2 + 0 + 2
f(0) = 2
(Graph attached)
From the graph we know the smallest positive integer value that the intermediate value theorem guarantees a zero exists between 0 and a is 3
For proof, the zero exists when x = 2 and f(3) = -4 < 0 and f(0) = 2 > 0.
<em>Your question is not complete, but most probably your full questions was</em>
<em>Given the polynomial f(x)=− x 2 +x+2 , what is the smallest positive integer a such that the Intermediate Value Theorem guarantees a zero exists between 0 and a ?</em>
Thus, the smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.
Learn more about intermediate value theorem here:
brainly.com/question/28048895
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The answer is 9:16 just add 9+7=16 and then we know out of the 16 nine were dogs so 9:16
Answer: (fg)(x) = 6x^2 + 11x - 7
Explanation:
(2x - 1)(3x + 7)
= 6x^2 + 14x -3x -7
= 6x^2 + 11x - 7
we have

we know that
If the point is an equation solution, it must satisfy the equation.
<u>case a</u>) 
Substitute the values of x and y in the equation


-------> the point is not solution of the equation
<u>case b</u>) 
Substitute the values of x and y in the equation


-------> the point is solution of the equation
<u>case c</u>) 
Substitute the values of x and y in the equation


-------> the point is not solution of the equation
<u>case d</u>) 
Substitute the values of x and y in the equation

-------> the point is not solution of the equation
therefore
<u>the answer is</u>
The point
is solution of the equation