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Arturiano [62]
2 years ago
10

4 Cx+4)=32 4X+16=32 Helppp find x

Mathematics
1 answer:
Leona [35]2 years ago
4 0

Answer:

x=4

Step-by-step explanation:

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qwelly [4]

Answer:collecting data

Step-by-step explanation:

7 0
2 years ago
A landscaper buys 1 gallon of plant fertilizer. He uses 1/5 of the fertilizer, and then divides the rest into 3 smaller bottles.
PIT_PIT [208]

Answer:

\frac{4}{15} of a gallon per bottle

Step-by-step explanation:

1 - \frac{1}{5} = \frac{4}{5}

\frac{4}{5} / 3 = \frac{4}{5} x \frac{1}{3} = \frac{4}{15}

5 0
2 years ago
Rewrite 9^4 * 10^4 as a single power
Vlada [557]

Answer:

90^8

Step-by-step explanation:

5 0
3 years ago
Which equation is equivalent to 16 Superscript 2 p Baseline = 32 Superscript p 3?.
Mrac [35]

The equation which is equivalent to 16 Superscript 2 p Baseline equal to 32 Superscript p 3 is,

2^{8p}=2^{5p+15}

<h3>What is equivalent equation?</h3>

Equivalent equation are the expression whose result is equal to the original expression, but the way of representation is different.

Given information-

The given equation in the problem is,

16^{2p}=32^{p+3}

Write both the equation in the form of same base number as,

(2^4)^{2p}=(2^5)^{p+3}

The power of the power of a number can be written as product of both the numbers. Thus,

(2)^{4\times2p}=(2)^{5\times(p+3)}\\2^{8P}=2^{5P+15}

This is the required equation.

Now if the base is the same at both side of the expression, then the powers can be compared. Thus,

8p=5p+15

Solve it further to find the value of p as,

8p-5p=15\\3p=15\\p=5

Thus the equation which is equivalent to 16 Superscript 2 p Baseline equal to 32 Superscript p 3 is,

2^{8p}=2^{5p+15}

Learn more about the equivalent expression here;

brainly.com/question/2972832

7 0
2 years ago
Help with the 2 question .. 20 points
Bas_tet [7]

Answer:

see explanation

Step-by-step explanation:

c = a - 2b

  = < 4, 5, 6 > - 2 < 1, 2, 3 > ← multiply each component by 2

  = < 4, 5, 6 > - < 2, 4, 6 >  ← subtract corresponding components

  = < 4 - 2, 5 - 4, 6 - 6 > = < 2, 1, 0 >

| c | = \sqrt{2^2+1^2+0^2} = \sqrt{4+1+0} = \sqrt{5}

-------------------------------------------------------------------------------------------------

sum the product of corresponding components

u.v = (3 × 2) + (- 2 × - 1) + (4 × - 6) = 6 + 2 - 24 = - 16

6 0
3 years ago
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