(-5+i)/2i
multiply by i/i
(-5+i) *i = -5i +i^2 = -5i -1
2i*i = 2i^2 = 2(-1) = -2
(-1-5i)/-2
1/2 +5/2 *i
Answer:
C, D, E
Step-by-step explanation:
l×w×h
Length and width are n
Height is 6
Plug them into the equation, the order can be changed. Also, n^2 is the same as n×n. Hope this helped you.
1,2,4,5,10,20
42 is the answer to your question
Answer:
shape AREA= 35cm^2
Step-by-step explanation:
you should know that this shape is a combination of triangle and trapezoid. therefore you have to find the area of each shape and add them.
A=h/2(b1 + b2) for trapezoid
A=2/2((4+4)+4)
A=1*12
A=12cm^2
A=bh/2. for TRIANGLE
A=1/2((4+4)*5.75)
A=1/2(46)
A=23cm^2
shape AREA= triangle AREA + trapezoid AREA
shape AREA=12cm^2 + 23cm^2
shape AREA= 35cm^2
Answer:
Step-by-step explanation:
Let the number of cars be x and buses be y
<u>Then we have below inequalities as per given:</u>
- 5x + 32y ≤ 1310
- x + y ≤ 135
It is easy to notice that cars occupy 6 times less area than buses but cost of parking is 3 times less. So we would need maximum number of cars and minimum number of buses to maximize income
<u>Let's assume there are 135 cars and buses, then from the second inequality:</u>
<u>Substitute it in the first one:</u>
- 5(135 - y) + 32y ≤ 1310
- 675 - 5y + 32y ≤ 1310
- 27y ≤ 1310 - 675
- 27y ≤ 635
- y ≤ 635/27
- y≤ 23.5
The greatest number of buses is 23
Option D. 23 is correct