Question

B b {?}^{3 } - c {?}^{3} " alt="b {?}^{3 } - c {?}^{3} " align="absmiddle" class="latex-formula">
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Answer 1

Answer:

$b^3-c^3=(b-c)(b^2+c^2+bc)$

Explanation:

We need to write the value of $b ^{3 } - c ^3$. It is a well known identity of algebra.

$b^3-c^3=(b-c)(b^2+c^2+bc)$

Here,

b and c are any number.

We know that,

b² = b×b

bc = b × c

Hence, this is the required solution.