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prohojiy [21]
3 years ago
10

8 2/3 + (-2 1/12)= what would that be

Mathematics
1 answer:
miv72 [106K]3 years ago
3 0

Answer:

307/12

(Decimal: 25.583333)

Step-by-step explanation:

Heart if this helped

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Round 34,576 to the nearest thousand
VARVARA [1.3K]

Answer:

35000

Step-by-step explanation:

6 0
3 years ago
What is the slope of the line 6x – 2y – 14 = 0?
fredd [130]

Answer:

3

Step-by-step explanation:

8 0
3 years ago
the area of a triangle is 124 square units. what would it's new area be if its base was half as long and its height was three ti
Montano1993 [528]
To solve this problem you must apply the proccedure shown below:

 1. You have that the formula for calculate the area of a triangle is:

 A=bh/2

 Where A is the area of the triangle, b is the base of the triangle and h is the height of the triangle.

 bh/2=124
 bh=124x2
 bh=248

 2. The problem asks for the new area of the triangle <span>if its base was half as long and its height was three times as long. Then, you have:

 Base=b/2
 Height=3h

 3. Therefore, when you substitute this into the formula for calculate the area of a triangle, you obtain:

 A'=bh/2

 (A' is the new area)

 A'=(b/2)(3)/2
 A'=3bh/4

 4. When you substitute bh=248 into </span>A'=3bh/4, you obtain:
<span>
 A'=186 units</span>²
<span>
 The answer is: </span>186 units²
3 0
4 years ago
7x+6= 5(x+2)<br>help me​
Zigmanuir [339]

\huge \pink{solution}

Given :7x+6=5(x+2)

Now We will use the distributive property to multiply 5 by x+2.

→7x+6=5x+10

We will Subtract 5x from both sides.

→7x+6−5x=10

We will Combine 7x and −5x to get 2x.

→2x+6=10

We will Subtract 6 from both sides.

2x=10−6

We will Subtract 6 from 10 to get 4.

2x=4

We will Divide both sides by 2.

x= 4/2

At last,We Divide 4 by 2 to get 2.

x=2

7 0
3 years ago
Read 2 more answers
Determine the first four terms of the sequence in which the nth term is...
Anon25 [30]

Answer:

1/5, 1/6, 1/7, 1/8

Step-by-step explanation:

The formula for the sequence is (n+3)!/ (n+4)!

The first terms uses n=1

a1 = (1+3)!/ (1+4)! = 4!/5! = (4*3*2*1)/(5*4*3*2*1) = 1/5


The first terms uses n=2

a2 = (2+3)!/ (2+4)! = 5!/6! = (5*4*3*2*1)/(6*5*4*3*2*1) = 1/6


The first terms uses n=3

a3 = (3+3)!/ (3+4)! = 6!/7! = (6*5*4*3*2*1)/(7*6*5*4*3*2*1) = 1/7


The first terms uses n=4

a4 = (4+3)!/ (4+4)! = 7!/8! = (7*6*5*4*3*2*1)/(8*7*6*5*4*3*2*1) = 1/8

7 0
4 years ago
Read 2 more answers
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