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2 years ago

Please help ASAP on question b

Mathematics

2 answers:

max2010maxim [7]2 years ago

8 0

Answer:

13.9cm

Step-by-step explanation:

13^2 = 169

5^2 = 25

169 + 25

= 194

13.9

irga5000 [103]2 years ago

3 0

Answer:

13.9283882772

Step-by-step explanation:

5^2 + 13^2 = c^2

25 + 169 = 194, so you find the square root of 194 which is 13.9283882772

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Certain tubes manufactured by a company have a mean lifetime of 800 hours and a standard deviation of 60 hours. Find the probabi

Anna71 [15]

Answer:

Step-by-step explanation:

given that certain tubes manufactured by a company have a mean lifetime of 800 hours and a standard deviation of 60 hours.

Sample size n =16

Std error of sample mean = $\frac{\sigma}{\sqrt{n} } \\= 15$

x bar follows N(800, 15)

the probability that a random sample of 16 tubes taken from the group will have a mean lifetime

(a) between 790 and 810 hours,

= $P(790$

(b) less than 785 hours

$=P(X$

, (c) more than 820 hours,

$=P(X>820)\\=p(Z>1.333)\\= 0.0913$

(d) between 770 and 830 hours

= $P(|Z|$

4 0

2 years ago

Help pls I need help my grades go in in a couple mins

julsineya [31]

Answer:

16g

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Can someone teach me how to solve this please

Alexeev081 [22]

Multiply it all together

7 0

3 years ago

.Resolva as equações, sendo U = Q (separe as respostas por vírgulas). A) 3y - 2 = - y + 4 B) 5 - 4x = x + 3 + 2x C) - 12 - 9x =

Oxana [17]

Answer:

$(A) y=1.5$

$(B)x=\dfrac27$

$(C)x=2\dfrac23$

$(D)x=-5.25$

Step-by-step explanation:

(A)

$3y - 2 = - y + 4\\3y+y=4+2\\4y=6\\y=\dfrac64\\\\y=1.5$

(B)

$5 - 4x = x + 3 + 2x\\5 - 4x = 3 +3x\\5-3=3x+4x\\7x=2\\x=\dfrac27$

(C)

$-12 - 9x = - 4 - 12x\\-9x+12x=-4+12\\3x=8\\x=\dfrac83\\\\x=2\dfrac23$

(D) $- x - 6 + 3x = -2x + 8x + 15$

$2x-6 = 6x + 15\\2x-6x=15+6\\-4x=21\\x=\dfrac{21}{-4} \\\\x=-5.25$

5 0

2 years ago

What is the first derivative of r with respect to t (i.e., differentiate r with respect to t)? r = 5/(t2)Note: Use ^ to show exp

adelina 88 [10]

Answer:

The first derivative of $r(t) = 5\cdot t^{-2}$ (r(t)=5*t^{-2}) with respect to t is $r'(t) = -10\cdot t^{-3}$ (r'(t) = -10*t^{-3}).

Step-by-step explanation:

Let be $r(t) = \frac{5}{t^{2}}$ , which can be rewritten as $r(t) = 5\cdot t^{-2}$ . The rule of differentiation for a potential function multiplied by a constant is:

$\frac{d}{dt}(c \cdot t^{n}) = n\cdot c \cdot t^{n-1}$ , $\forall \,n\neq 0$

Then,

$r'(t) = (-2)\cdot 5\cdot t^{-3}$

$r'(t) = -10\cdot t^{-3}$ (r'(t) = -10*t^{-3})

The first derivative of $r(t) = 5\cdot t^{-2}$ (r(t)=5*t^{-2}) with respect to t is $r'(t) = -10\cdot t^{-3}$ (r'(t) = -10*t^{-3}).

5 0

3 years ago