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3 years ago

Jonathan is deciding between two truck rental companies. Company A

Mathematics

1 answer:

hjlf3 years ago

3 0

Answer:

Jonathan is deciding between two truck rental companies. Company A

charges an initial fee of go for the rental plus $1 per mile driven

Company B charges an initial fee of $10 for the rental plus $1.50 per

mile driven. Let A represent the amount Company A would charge if

Jonathan drives s miles, and let B represent the amount Company B

would charge if Jonathan drives s miles, Graph each function and

determine which company would be cheaper if Jonathan needs to

drive 60 miles with the rented truck,

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Find the partial fraction decomposition of the rational expression with prime quadratic factors in the denominator

SpyIntel [72]

$\dfrac{5x^4-7x^3-12x^2+6x+21}{(x-3)(x^2-2)^2}=\dfrac{a_1}{x-3}+\dfrac{a_2x+a_3}{x^2-2}+\dfrac{a_4x+a_5}{(x^2-2)^2}$
$\implies 5x^4-7x^3-12x^2+6x+21=a_1(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(a_4x+a_5)(x-3)$

When $x=3$ , you're left with

$147=49a_1\implies a_1=\dfrac{147}{49}=3$

When $x=\sqrt2$ or $x=-\sqrt2$ , you're left with

$\begin{cases}17-8\sqrt2=(\sqrt2a_4+a_5)(\sqrt2-3)&\text{for }x=\sqrt2\\17+8\sqrt2=(-\sqrt2a_4+a_5)(-\sqrt2-3)\end{cases}\implies\begin{cases}-5+\sqrt2=\sqrt2a_4+a_5\\-5-\sqrt2=-\sqrt2a_4+a_5\end{cases}$

Adding the two equations together gives $-10=2a_5$ , or $a_5=-5$ . Subtracting them gives $2\sqrt2=2\sqrt2a_4$ , $a_4=1$ .

Now, you have

$5x^4-7x^3-12x^2+6x+21=3(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(x-5)(x-3)$
$5x^4-7x^3-12x^2+6x+21=3x^4-11x^2-8x+27+(a_2x+a_3)(x-3)(x^2-2)$
$2x^4-7x^3-x^2+14x-6=(a_2x+a_3)(x-3)(x^2-2)$

By just examining the leading and lagging (first and last) terms that would be obtained by expanding the right side, and matching these with the terms on the left side, you would see that $a_2x^4=2x^4$ and $a_3(-3)(-2)=6a_3=-6$ . These alone tell you that you must have $a_2=2$ and $a_3=-1$ .

So the partial fraction decomposition is

$\dfrac3{x-3}+\dfrac{2x-1}{x^2-2}+\dfrac{x-5}{(x^2-2)^2}$

7 0

3 years ago

How would you solve this? help.

Eddi Din [679]

Answer:

Center: (3,3)

Radius: $2\sqrt{5}$

Step-by-step explanation:

Midpoint and Distance Between two Points

Given two points A(x1,y1) and B(x2,y2), the midpoint M(xm,ym) between A and B has the following coordinates:

$\displaystyle x_m=\frac{x_1+x_2}{2}$

$\displaystyle y_m=\frac{y_1+y_2}{2}$

The distance between both points is given by:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Point (5,7) is the center of circle A, and point (1,-1) is the center of the circle B. Given both points belong to circle C, the center of C must be the midpoint from A to B:

$\displaystyle x_m=\frac{5+1}{2}=\frac{6}{2}=3$

$\displaystyle y_m=\frac{7-1}{2}=\frac{6}{2}=3$

Center of circle C: (3,3)

The radius of C is half the distance between A and B:

$d=\sqrt{(1-5)^2+(-1-7)^2}$

$d=\sqrt{16+64}=\sqrt{80}=\sqrt{16*5}=4\sqrt{5}$

The radius of C is d/2:

$r =4\sqrt{5}/2 = 2\sqrt{5}$

Center: (3,3)

Radius: $2\sqrt{5}$

8 0

3 years ago

Determine whether the vectors u and v are parallel, orthogonal, or neither. u = <6, -2>, v = <8, 24>

ratelena [41]

We'll check if they're orthogonal:
u*v=0
(6,-2)*(8,24)=0
6*8+(-2)*24=0
48-48=0
0=0
they are orthogonal vectors

4 0

3 years ago

The line plot shows the results of a survey of 10 boys and 10 girls about how many hours they spent reading for pleasure the pre

elena-14-01-66 [18.8K]

10 students per gender:

Boys: four Xs over five and one X over zero, two, three, four, ten, and twelve.
5, 5, 5, 5, 0, 2, 3, 4, 10, 12 → 0, 2, 3, 4, 5, 5, 5, 5, 10, 12
mean: 5.1
range: 12

Girls: three Xs above eight, two Xs above three and four, and one X above two, six and seven.
8, 8, 8, 3, 3, 4, 4, 2, 6, 7 → 2, 3, 3, 4, 4, 6, 7, 8, 8, 8
mean: 5.3
range: 6

The boys have the higher range while the girls have the higher mean value.

8 0

3 years ago

Which of the following transformations maps A to A’ in the figure below

LenKa [72]

Answer:

The answer is rotation 270° about the origin

Step-by-step explanation:

If (x , y) is a point in xy-coordinates

If the point rotate about the origin ⇒ (The positive direction is anti-clockwise)

1- 90°

Its image is (-y , x)

2- 180°

Its image is (-x , -y)

3- 270°

Its image is (y , -x)

If we assume A is (1 , 7)

1- ⇒ (-7 , 1) ⇒ rotation 90° about the origin

2- ⇒ (-1 , -7) ⇒ rotation 180° about the origin

3- ⇒ (7 , -1) ⇒ rotation 270° about the origin

∵ x-coordinate of point A small and +ve and y-coordinate large and +ve

∵ x-coordinate of point A' large and +ve and y-coordinate small and -ve

∴ The answer is rotation 270° about the origin

8 0

3 years ago

Read 2 more answers