An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.
1 answer:
Answer:
The probability that A selects the first red ball is 0.5833.
Step-by-step explanation:
Given : An urn contains 3 red and 7 black balls. Players A and B take turns (A goes first) withdrawing balls from the urn consecutively.
To find : What is the probability that A selects the first red ball?
Solution :
A wins if the first red ball is drawn 1st,3rd,5th or 7th.
A red ball drawn first, there are places in which the other 2 red balls can be placed.
A red ball drawn third, there are places in which the other 2 red balls can be placed.
A red ball drawn fifth, there are places in which the other 2 red balls can be placed.
A red ball drawn seventh, there are places in which the other 2 red balls can be placed.
The total number of total event is
The probability that A selects the first red ball is
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Answer:
Step-by-step explanation:
So we have:
And we want to find dy/dx.
So, let's take the derivative of both sides with respect to x:
Let's do each side individually.
Left Side:
We have:
We can use the product rule:
So, our derivative is:
We must implicitly differentiate for y. This gives us:
For the sin(y), we need to use the chain rule:
Our u(x) is sin(x) and our v(x) is y. So, u'(x) is cos(x) and v'(x) is dy/dx.
So, our derivative is:
Simplify:
And we are done for the right.
Right Side:
We have:
This will be significantly easier since it's just x like normal.
Again, let's use the product rule:
Differentiate:
So, our entire equation is:
To find our derivative, we need to solve for dy/dx. So, let's factor out a dy/dx from the left. This yields:
Finally, divide everything by the expression inside the parentheses to obtain our derivative:
And we're done!