4x^2 + 5xy - y^2 = 6
Implicitly differentiating both sides,
4(2x) + 5(x y' + y) - 2yy' = 0
where y' = dy/dx
8x + 5xy' +5y -2yy' = 0
combining y' terms
y' (5x-2y) +8x +5y = 0
y'(5x-2y) = -(8x+5y)
dy/dx = -(8x+5y)/(5x-2y)
or
dy/dx = (8x+5y)/(2y-5x)
Answer:
C-----> x<-7
Step-by-step explanation:
first u do this to turn x in positive and consequently change the > to an <:
(-1).(-4x)>28.(-1)
so:
4x<-28
x<-7
# when multiplying each side by (-1), you have to change the symbol (>) to an (<), or (<) to an (>)
it took me a while but the answer is 5/3
Answer:
2z^3 - 5z^2 + 4z - 1
Step-by-step explanation:
(2z - 1)(z^2 – 2z+ 1) =
= 2z^3 - 4z^2 + 2z - z^2 + 2z - 1
= 2z^3 - 5z^2 + 4z - 1
