Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.
2(x+y) = 300
x+y = 150
y = 150-x
A=x(150-x) <--(substitution)
The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
0=x(150-x)
x=0, 150
So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.
A=75(150-75)
A=75*75
A=5625
So the maximum area that can be enclosed is 5625 square feet.
1. Let x be the original amount of baseball cards,
2. half of x was lost so x divided by 2.
3. you buy 18 cards to replace some that were lost
4. You can find the awnser by subtracting 18 from 30, which is 12.
5. Now lets remember that half of your cards were lost. meaning that 12 is only half of what you started with.
6. 12 times 2 would be 24.
7. The Awnser is 24
8. To check your work, you can say x=24, 24 divided by 2 is 12, and 12 plus 18 is 30.
It would be:
-.72 < -5/8 < -.6 < -7/12
Considering 1.824 (2 being hundredth) it would mean that this is 1.82 <span />
A mean is the total of all numbers/ how many numbers there are.
A median is a middle number. An equation you can use is (x+1/2). x is how many numbers there are
