Answer:
76 on second exam, 80 on third exam
Step-by-step explanation:
First, find the total of all 3 test scores by multiplying the average by the number of elements. 81 · 3 = 243.
The first score is 83 so 243 - 83 = 160. 160 is the other two test scores combined.
To find the other 2 scores, divide 160 by 2, which is 80.
The second score is 4 less so it will be 76. The third score is 80.
Answer:
Step-by-step explanation:
Hello!
X: number of absences per tutorial per student over the past 5 years(percentage)
X≈N(μ;σ²)
You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.
The formula for the CI is:
X[bar] ±
* 
⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.
Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4
X[bar]= 10.41
S= 3.71

[10.41±1.645*
]
[9.26; 11.56]
Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.
I hope this helps!
Answer:
what are the equations to the math on this?
Answer:
a: x = -4
b: x = 4
c: y = 4
d: y = -2
e: y = -3/4x + 1
Step-by-step explanation: