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Sliva [168]
3 years ago
6

Solve y - 3x = 13 for y y = ?

Mathematics
1 answer:
vampirchik [111]3 years ago
3 0

Answer:

y = 3x + 13

Step-by-step explanation:

Here, we want to solve for y

To solve for y, we simply are going to make y the subject of the formula

We have this as;

y - 3x = 13

y = 13 + 3x

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Determine which of the ordered pairs are a part of the solution set of y + 3 < 2x (0, –4)
lorasvet [3.4K]

Answer:

(2,0) and (2,-2)

Step-by-step explanation:

y+3<2x

(2,0) is solution because 0+3<2*2, 3<4 and

(2,-2) because - 2+3<2*2, 1<4

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4 years ago
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A newspaper plans to conduct a survey for the upcoming presidential election in order to estimate the proportion of the populati
xxTIMURxx [149]

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660

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3 years ago
Round the number 14.63157 to the nearest ten-thousandth.
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Answer:

14.6316

Step-by-step explanation:

The place value ten-thousandth falls on number 5. The following number is 7 and because 7 is greater than 5, "5" turns into 6.

Hope it helps!

8 0
3 years ago
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Maura writes an expression equivalent to 8a - (-3 - 5a) - 2a. Her work is in the picture. In what step does Maura make a mistake
NISA [10]

Answer:

11a + 3

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Step 1 : 8a + 3 - 5a - 2a

error => - 5a

8a - (- 3 - 5a) - 2a =

= 8a + 3 + 5a - 2a

= (8a + 5a - 2a) + 3

= 11a + 3

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3 years ago
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According to Masterfoods, the company that manufactures M&amp;M’s, 12% of peanut M&amp;M’s are brown, 15% are yellow, 12% are re
Anna35 [415]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

P(brown) = 12% = 0.12

P(Yellow) = 15% = 0.15

P(Red) = 12% = 0.12

P(blue) = 23% = 0.23

P(orange) = 23% = 0.23

P(green) = 15% = 0.15

A.) Compute the probability that a randomly selected peanut M&M is not yellow.

P(not yellow) = P(Yellow)' = 1 - P(Yellow) = 1 - 0.15 = 0.85

B.) Compute the probability that a randomly selected peanut M&M is brown or red.

P(Brown) or P(Red) :

0.12 + 0.12 = 0.24

C.) Compute the probability that three randomly selected peanut M&M’s are all brown.

P(brown) * P(brown) * P(brown)

0.12 * 0.12 * 0.12 =0.001728

D.) If you randomly select three peanut M&M’s, compute that probability that none of them are blue.

P(3 blue)' = 1 - P(3 blue)

P(3 blue) = 0.23 * 0.23 * 0.23 = 0.012167

1 - P(3 blue) = 1 - 0.012167 = 0.987833

If you randomly select three peanut M&M’s, compute that probability that at least one of them is blue.

P(1 blue) + p(2 blue) + p(3 blue)

(0.23) + (0.23*0.23) + (0.23*0.23*0.23)

0.23 + 0.0529 + 0.012167

= 0.295067

5 0
3 years ago
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