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3 years ago

Eight greater than twice the number

Mathematics

1 answer:

Lady_Fox [76]3 years ago

7 0

X times 2 plus 8 (hope this helps cuz I don't know what it asking)

Step-by-step explanation:

X times 2 plus 8

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Help, need answer. do not need to be worked out

miv72 [106K]

Answer:

B 98

Step-by-step explanation:

4*7=28 times 3 = 84

3.5*4=14

84+14=98

Hope this helps! :)

3 0

2 years ago

Read 2 more answers

Help!!! Just those two, please

Lunna [17]

A. Multiply the area of the original store by the percent increase then add that to the original amount.

1200 x 0.75 = 900

1200 + 900 = 2100

Answer: 2,100 square feet.

B. 2000 x 0.30 = 600

2000 + 600 = $2,600

2600 x 0.05 = 130

2600 + 130 = 2,730

Rent :$2,730

4 0

2 years ago

Boa tarde gentiii Abaixo aparecem quatro sequências. Defina cada uma delas como RECURSIVA ou NÃO RECURSIVA. a) (5, 7, 9, 11, 13,

marusya05 [52]

Answer:

a) (5, 7, 9, 11, 13, 15, 17, 19, ...) Recursivo

b) (1, 4, 9, 16, 25, 36, 49, 64, ...) Recursivo

c) (1, 8, 27, 64, ...) Recursivo

d) (2, 5, 8, 11, 14, 17, ...) Recursivo

Step-by-step explanation:

Uma função recursiva é aquela em que os termos subsequentes da função são calculados com base nos termos anteriores

O comportamento recursivo é exibido pelos objetos quando consiste em seguir as partes;

1) Uma base que é predefinida

2) Um processo ou etapa recursiva que produz termos subsequentes pela aplicação de certos processos

Para a série;

a) (5, 7, 9, 11, 13, 15, 17, 19, ...)

Aqui 5 é a base e os termos subsequentes são encontrados adicionando 2 ao termo anterior, portanto, é uma função recursiva

aₙ = aₙ₋₁ + 2

b) (1, 4, 9, 16, 25, 36, 49, 64, ...)

Aqui 1 é a base e os termos subsequentes são encontrados ao quadrado da soma da raiz do termo anterior e 1, portanto, é uma função recursiva

aₙ = (√ (aₙ₋₁) + 1) ²

c) (1, 8, 27, 64, ...)

Aqui 1 é a base e os termos subsequentes são encontrados elevando à potência de três a soma da raiz cúbica do termo anterior e 1, portanto, é uma função recursiva

aₙ = (∛ (aₙ₋₁) + 1) ³

d) (2, 5, 8, 11, 14, 17, ...)

Aqui 2 é a base e os termos subsequentes são encontrados adicionando 3 ao termo anterior, portanto, é uma função recursiva.

7 0

3 years ago

Solve the compound inequality 7x > –35 and 3x ≤ 30.

docker41 [41]

Answer:

x>-5 x ≤10

Step-by-step explanation:

-35/7=-5

7x/7=x

3x/3=x

30/3=10

5 0

2 years ago

Consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular paint company. Suppose that a norm

Artemon [7]

Answer:

a) 0.5.

b) 0.8413

c) 0.8413

d) 0.6826

e) 0.9332

f) 1

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 6, \sigma = 0.2$

(a) P(x > 6) =

This is 1 subtracted by the pvalue of Z when X = 6. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6-6}{0.2}$

$Z = 0$

$Z = 0$ has a pvalue of 0.5.

1 - 0.5 = 0.5.

(b) P(x < 6.2)=

This is the pvalue of Z when X = 6.2. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6.2-6}{0.2}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413

(c) P(x ≤ 6.2) =

In the normal distribution, the probability of an exact value, for example, P(X = 6.2), is always zero, which means that P(x ≤ 6.2) = P(x < 6.2) = 0.8413.

(d) P(5.8 < x < 6.2) =

This is the pvalue of Z when X = 6.2 subtracted by the pvalue of Z when X 5.8.

X = 6.2

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{6.2-6}{0.2}$

$Z = 1$

$Z = 1$ has a pvalue of 0.8413

X = 5.8

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5.8-6}{0.2}$

$Z = -1$

$Z = -1$ has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

(e) P(x > 5.7) =

This is 1 subtracted by the pvalue of Z when X = 5.7.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5.8-6}{0.2}$

$Z = -1.5$

$Z = -1.5$ has a pvalue of 0.0668

1 - 0.0668 = 0.9332

(f) P(x > 5) =

This is 1 subtracted by the pvalue of Z when X = 5.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5-6}{0.2}$

$Z = -5$

$Z = -5$ has a pvalue of 0.

1 - 0 = 1

5 0

3 years ago