A = c/sin C, and b by the proportion b/sin B = c/sin C.
a/sin 37° = 4380/sin 109°
a sin 109° = 4380 sin 37°
a = 4380 sin 37°/sin 109° ≈ 2787.8
b/sin 34° = 4380/sin 109°
b sin 109° = 4380 sin 34°
b = 4380 sin 34°/sin 109° ≈ 2590.4
Answer:
198 feet per minute
Step-by-step explanation:
8910 feet ÷ 45 minutes = 198 feet per minute
Answer:
yes that are similar
Step-by-step explanation:
because the angles are both 50 degrees
similarity statement:
triangle DEF= triangle JEH
hope that helps bby<3
Answer:
#TEAM BOB
FOR BOB!!!!!!!
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Copy and paste to help Bob.
We can do it together!#TEAM BOB
FOR BOB!!!!!!!
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░░░▌░▄▄▄▐▌▀▀▀░░ Dis is Bob
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Copy and paste to help Bob.
We can do it together!
Step-by-step explanation:
Answer:
16 km due west
Step-by-step explanation:
The bearing of the school p from school q is 16 km due west.
To find the bearing of school q from school p, we have to find the direction that the school q is with respect to school p.
Since p is directly west of q, then it implies that q must be directly east of p.
We now know the direction.
Since the distance from q to p is exactly the same as the distance from p to q, then, the distance from p to q is 16 km.
Hence, the bearing of q from p is 16 km due west.
