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PSYCHO15rus [73]
3 years ago
6

HELPPP I WILL BRAINLIST!!

Mathematics
1 answer:
charle [14.2K]3 years ago
3 0

Answer:

Step-by-step explanation:

8 (x -3) +7 = 2x (4 -17)

8(x -3) +7 = 2x (-13)   here was the error because the had 13 that is incorrect

8x -24 +7 = -26x

8x -17 = -26x

-17 = -26x -8x

-17 = -34x

-17/-34 = x

1/2 =x

You might be interested in
Which of the following proportions could be used to convert 6 days to hours?
nekit [7.7K]

Answer:

Step-by-step explanation:

24 hours---------->1 day

x hours------------>6 days

Cross multiplying:

x=24x6

x=144 hrs

4 0
3 years ago
Let X denote the amount of time a book on two-hour reserve is actually checked out, and suppose the cdf is the following. F(x) =
Troyanec [42]

Answer:

a) P (x <= 3 ) = 0.36

b) P ( 2.5 <= x <= 3  ) = 0.11

c) P (x > 3.5 ) = 1 - 0.49 = 0.51

d) x = 3.5355

e) f(x) = x / 12.5

f) E(X) = 3.3333

g) Var (X) = 13.8891  , s.d (X) = 3.7268

h) E[h(X)] = 2500

Step-by-step explanation:

Given:

The cdf is as follows:

                           F(x) = 0                  x < 0

                           F(x) = (x^2 / 25)     0 < x < 5

                           F(x) = 1                   x > 5

Find:

(a) Calculate P(X ≤ 3).

(b) Calculate P(2.5 ≤ X ≤ 3).

(c) Calculate P(X > 3.5).

(d) What is the median checkout duration ? [solve 0.5 = F()].

(e) Obtain the density function f(x). f(x) = F '(x) =

(f) Calculate E(X).

(g) Calculate V(X) and σx. V(X) = σx =

(h) If the borrower is charged an amount h(X) = X2 when checkout duration is X, compute the expected charge E[h(X)].

Solution:

a) Evaluate the cdf given with the limits 0 < x < 3.

So, P (x <= 3 ) = (x^2 / 25) | 0 to 3

     P (x <= 3 ) = (3^2 / 25)  - 0

     P (x <= 3 ) = 0.36

b) Evaluate the cdf given with the limits 2.5 < x < 3.

So, P ( 2.5 <= x <= 3 ) = (x^2 / 25) | 2.5 to 3

     P ( 2.5 <= x <= 3  ) = (3^2 / 25)  - (2.5^2 / 25)

     P ( 2.5 <= x <= 3  ) = 0.36 - 0.25 = 0.11

c) Evaluate the cdf given with the limits x > 3.5

So, P (x > 3.5 ) = 1 - P (x <= 3.5 )

     P (x > 3.5 ) = 1 - (3.5^2 / 25)  - 0

     P (x > 3.5 ) = 1 - 0.49 = 0.51

d) The median checkout for the duration that is 50% of the probability:

So, P( x < a ) = 0.5

      (x^2 / 25) = 0.5

       x^2 = 12.5

      x = 3.5355

e) The probability density function can be evaluated by taking the derivative of the cdf as follows:

       pdf f(x) = d(F(x)) / dx = x / 12.5

f) The expected value of X can be evaluated by the following formula from limits - ∞ to +∞:

         E(X) = integral ( x . f(x)).dx          limits: - ∞ to +∞

         E(X) = integral ( x^2 / 12.5)    

         E(X) = x^3 / 37.5                    limits: 0 to 5

         E(X) = 5^3 / 37.5 = 3.3333

g) The variance of X can be evaluated by the following formula from limits - ∞ to +∞:

         Var(X) = integral ( x^2 . f(x)).dx - (E(X))^2          limits: - ∞ to +∞

         Var(X) = integral ( x^3 / 12.5).dx - (E(X))^2    

         Var(X) = x^4 / 50 | - (3.3333)^2                         limits: 0 to 5

         Var(X) = 5^4 / 50 - (3.3333)^2 = 13.8891

         s.d(X) = sqrt (Var(X)) = sqrt (13.8891) = 3.7268

h) Find the expected charge E[h(X)] , where h(X) is given by:

          h(x) = (f(x))^2 = x^2 / 156.25

  The expected value of h(X) can be evaluated by the following formula from limits - ∞ to +∞:

         E(h(X))) = integral ( x . h(x) ).dx          limits: - ∞ to +∞

         E(h(X))) = integral ( x^3 / 156.25)    

         E(h(X))) = x^4 / 156.25                       limits: 0 to 25

         E(h(X))) = 25^4 / 156.25 = 2500

8 0
3 years ago
Find all the complex zeros for the polynomial function. show work<br> f(x)=x^3-7x^2+x-7
ANTONII [103]

Answer:

  ±i

Step-by-step explanation:

Observing that the first two coefficients are the same as the last two, we can factor this function by grouping.

  f(x) = (x^3 -7x^2) +(x -7) = x^2(x -7) +1(x -7)

  f(x) = (x^2 +1)(x -7)

The factor x-7 has a real zero at x=7, so the complex zeros come from the quadratic factor (x^2 +1).

Setting that to zero and solving for x, we find ...

  x^2 +1 = 0

  x^2 = -1

  x = ±√(-1) = ±i

The complex zeros are x = +i and x = -i.

3 0
3 years ago
Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real
adoni [48]

Step-by-step explanation

<h3>Prerequisites:</h3>

<u>You need to know: </u>

b^2 - 4ac = 0 \Rightarrow 1 solution

b^2 - 4ac > 0 \Rightarrow 2 solutions

b^2 - 4ac < 0 \Rightarrow No\ real\ solutions

----------------------------------------------------------------

2x^2-7x-9 = 0

b^2 - 4ac

-7^2 - 4(2)(-9) = 121

2 Solutions

---------------------------------------------------------------

x^2-4x+4 = 0

b^2 - 4ac

-4^2 - 4(1)(4) = 0

1 Solution

---------------------------------------------------------------

4x^2-3x-1 = 0

b^2 - 4ac

-3^2 - 4(4)(-1) = 25

2 Solutions

---------------------------------------------------------------

x^2-2x-8 = 0

b^2 - 4ac

-2^2 - 4(1)(-8) = 36

2 Solutions

---------------------------------------------------------------

3x^2+5x+3 = 0

b^2 - 4ac

5^2 - 4(3)(3) = -11

No Solutions

---------------------------------------------------------------


3 0
3 years ago
Read 2 more answers
According to the Rational Root Theorem, which number is a potential root of f(x) = 9x8 + 9x6 – 12x + 7?
AysviL [449]

Answer:

\pm 1, \pm\dfrac{1}{3},\pm\dfrac{1}{9},\pm 7, \pm\dfrac{7}{3},\pm\dfrac{7}{9}.

Step-by-step explanation:

According to the Rational Root Theorem, the potential roots of a polynomial are

x=\pm\dfrac{p}{q}  

where, p is a factor of constant and q is a factor of leading term.

The given polynomial is

f(x)=9x^8+9x^6-12x+7

Here, 9 is the leading term and 7 is constant.

Factors of 9 are ±1, ±3, ±9.

Factors of 7 are ±1, ±7.

Using rational root theorem, the rational or potential roots are

x=\pm 1, \pm\dfrac{1}{3},\pm\dfrac{1}{9},\pm 7, \pm\dfrac{7}{3},\pm\dfrac{7}{9}

Therefore, the potential root of f(x) are \pm 1, \pm\dfrac{1}{3},\pm\dfrac{1}{9},\pm 7, \pm\dfrac{7}{3},\pm\dfrac{7}{9}.  

4 0
3 years ago
Read 2 more answers
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