Answer:
qr=1.3
Step-by-step explanation:
9514 1404 393
Answer:
$2,104.33 at the beginning of the month, or
$2,111.35 at the end of the month
Step-by-step explanation:
The amount you can withdraw at the end of the month is given by the annuity formula ...
A = P(r/12)/(1 -(1 +r/12)^(-12t))
where principal P is earning annual rate r for t years
A = $400,000(0.04/12)/(1 -(1 +0.04/12)^(-12·25)) ≈ $2,111.35
If the withdrawal is at the beginning of the month, then the amount is less by a factor of (1+0.04/12) ≈ 1.003333. It will be $2,104.33.
Answer:
about 0.0927 seconds
Step-by-step explanation:
Put the given information into the given formula and solve for the remaining variable. It is a linear equation, solved in the usual way.
ln(0.430/0.750) = -7.50t/1.25 . . . substitute the given information
-ln(43/75)/6 = t ≈ 0.092714 . . . . . divide by the coefficient of t
Rounded to 3 significant figures, the time is 0.0927 seconds.
answer:there is no picture
Answer:
soccer balls = 80
basketballs = 120
Step-by-step explanation:
let S = number of soccer balls sold
let B = number of basketballs sold
If the store sold 40 more basketballs than soccer balls, then
B = S + 40
If the store sold $4800 worth of soccer and basketballs last month at a cost of $33 for a soccer ball and $18 for a basketball, then:
33S + 18B = 4800
Substitute the first equation B = S + 40 into the second equation and solve for S:
33S + 18(S + 40) = 4800
33S + 18S + 720 = 4800
51S + 720 = 4800
51S = 4080
S = 80
Substitute S = 80 into B = S + 40 to find B:
B = 80 + 40 = 120
