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malfutka [58]
3 years ago
5

In a hydraulic lift, a 1400 N force is applied to a 0.5 m2 piston. Calculate the minimum surface area of the large piston to lif

t 5000 N.
Mathematics
1 answer:
dexar [7]3 years ago
5 0

Answer:

1.8m^2 approx

Step-by-step explanation:

Given data

P1= 1400N

A1=0.5m^2

P2=5000 N

A2=??

Let us apply the formula to calculate the Area A2

P1/A1= P2/A2

substitute

1400/0.5= 5000/A2

cross multiply

1400*A2= 5000*0.5

1400*A2= 2500

A2= 2500/1400

A2= 1.78

Hence the Area is 1.8m^2 approx

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Vanyuwa [196]

Answer:

Range = $115

Variance = $1915.2857

Standard deviation = $43.764

Step-by-step explanation:

Given the data:

234 160 119 131 218 207 146 141

Arranging in ascending order :

119, 131, 141, 146, 160, 207, 218, 234

The range = maximum - minimum

The range = 234 - 119 = 115

The variance :

Σ(x - mean)²/n-1

The mean = Σx / n

The mean = 1356 / 8 = 169.5

Variance :

Σ(x - mean)² = (119-169.5)² + (131-169.5)² + (141-169.5)² + (146-169.5)² + (160-169.5)² + (207-169.5)² + (218-169.5)² + (234-169.5)² = 13407

n - 1 = 8 - 1 = 7

Variance = 13407 / 7 = 1915.2857

Standard deviation = √variance

Standard deviation = √1915.2857

Standard deviation = $43.764

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3 years ago
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3 years ago
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Determine whether each scale factor produces an expansion or a contraction under a dilation of the original image
blondinia [14]

Answer:

see the explanation

Step-by-step explanation:

we know that

If the absolute value of the scale factor is less than 1, then the dilation produces a contraction of the original image

If the absolute value of the scale factor is greater than 1, then the dilation produces an expansion of the original image

so

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1) -4

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2/3 < 1

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