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zaharov [31]
3 years ago
12

For the triangles described, which of the following statements must be true? In triangle DEF, DE=8 in., DF=23 in., and ∡D=16°. I

n triangle PQR, PQ=23 in., PR=8 in., and ∡P=16°. (1 point) ∠Q≅∠F ∠R≅∠F DE¯¯¯¯¯¯¯¯≅PQ¯¯¯¯¯¯¯¯ ∠E≅∠Q
Mathematics
1 answer:
Temka [501]3 years ago
7 0

Answer:

∠Q≅∠F

Step-by-step explanation:

Two triangles are said to be congruent if all the three sides of the triangles are equal and all the three angles are equal.

Given that: In triangle DEF, DE=8 in., DF=23 in., and ∡D=16°. In triangle PQR, PQ=23 in., PR=8 in., and ∡P=16°.

Hence we can say that ΔDEF is congruent to ΔPQR. According to the side-angle-side (SAS) triangle congruence theorem: If two sides and the included angle of one triangle are equal to two sides and the included angle of another triangle, the triangles are congruent.

Therefore:

DF = PQ, DE = PR, EF = RQ, ∠D = ∠P, ∠E = ∠R and ∠F = ∠Q

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1-2 Cos²25°÷(1-2sin²25)<br>​
shusha [124]

Answer:

have a good one

Step-by-step explanation:

6 0
2 years ago
Solve for x: x^4 = 3^x
sveticcg [70]
There are no algebraic methods for finding solutions to a general mix of exponential and polynomial terms. A graphing calculator can be helpful.

This equation has 3 real solutions, approximately ...
  x ∈ {-0.802246431546, 1.51677641228, 7.17475582739}

_____
In the folder "iteration for solutions" is an equation for Newton's method iteration, essentially, ...
  g(x) = x -f(x)/f'(x)
where f(x) is defined as shown in the picture.

Many graphing calculators can compute a numerical derivative, so you can essentially write the formula in this form without having to do the derivative-taking yourself. This calculator is nicely interactive, so the iteration result is produced at the same time the argument for g(x) is entered. Essentially, you write the answer by copying the answer using the 4-digit zero-crossing values shown on the graph as the iteration starting point.

5 0
3 years ago
The coordinates of polygon ABCD are A(-4,-1), B(-2,3), C(2,2), and D(4,-3). Use these coordinates to complete the sentences belo
PolarNik [594]

Answer:

The perimeter of polygon ABCD, to the nearest thousandth units is

22.227 units

The perimeter of polygon ABCD', to the nearest thousandth, would be 20.980 units

The area of polygon ABCD' is 19.5 units²

Step-by-step explanation:

The coordinates forming the polygon are

A (-4,-1), B(-2,3), C(2,2), and D(4,-3)

The perimeter then is given by the sum of the length of the sides as follows;

Length of line between two X and Y points distance, xi and yj apart is

length XY =  \sqrt{x^2+y^2}

Therefore, the length between points AB is

length AB = \sqrt{(-4 - (-2))^2+(-1-3)^2}

= \sqrt{(-4 +2)^2+(-4)^2} = \sqrt{-2^2+-4^2}  = \sqrt{20}  = 4.472 units

Similarly, length BC is given by

Length BC =  \sqrt{(-4)^2+1^2} =  \sqrt{17} = 4.123 units

Length CD = \sqrt{(-2)^2+5^2} =  \sqrt{29} = 5.385 units

Length DA = \sqrt{(8)^2+(-2)^2} =  \sqrt{68} = 8.246 units

The perimeter is equal to;

length AB + Length BC + Length CD + Length DA

= 4.472 + 4.123 + 5.385 + 8.246 = 22.227 units

If the point D is moved up 2 units and left 1 unit we have

D' = x-1, y+2 where x and y are the coordinates of point D

D(4, -3) → D'((4-1), (-3+2)) = D'(3, -1)

The length D'A =  \sqrt{(7)^2+(0)^2} =  \sqrt{49} =7 units

The perimeter of polygon ABCD'

length AB + Length BC + Length CD + Length D'A

= 4.472 + 4.123 + 5.385 + 7 = 20.980 units.

The area is given by the determinant of the 3 by 3 matrix using Cramer's Rule as follows

 S_{\bigtriangleup} = (\frac{1}{2})|x_1y_2+x_2y_3+x_3y_1-x_1y_3-x_2y_1-x_3y_2|

= (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

Triangle ABC we have

A(-4,-1)

B(-2,3)

C(2,2)

S_{{\bigtriangleup}ABC} = (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

=(\frac{1}{2})|(-4)(3-2)+(-2)(2-(-1)) +2((-1)-3)|

= =(\frac{1}{2})|-4-6 -8|= 9 units^2

Triangle ACD'

A(-4,-1)

C(2,2)

D'(3, -1)

S_{{\bigtriangleup}ACD'} = (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

=(\frac{1}{2})|(-4)(2+1)+(2)(-1+1) +3((-1)-2)| = \frac{21}{2} = 10.5 units²

Area of polygon =   S_{{\bigtriangleup}ABCD'} = S_{{\bigtriangleup}ABC} + S_{{\bigtriangleup}ACD'} = (9 + 10.5) units²

Area of polygon ABCD' = 19.5 units².

8 0
3 years ago
What is the rate of change and initial value for the linear relation that includes the points shown in the table?
defon

The initial value: 25, rate of change: -5 ⇒ answer C

Step-by-step explanation:

The table:

→  x  :    1    :    3    :    5    :    7

→  y  :    20 :    10  :    0    :    -10

The linear relation between x and y is y = m x + b, where

  • m is the rate of change
  • b is the initial value

Let us use the table to find m and b

∵ m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} , where (x_{1},y_{1})

   and (x_{2},y_{2}) are any two ordered pairs in the table

∵ (x_{1},y_{1}) = (1 , 20)

∵ (x_{2},y_{2}) = (3 , 10)

∴ m=\frac{10-20}{3-1}=\frac{-10}{2}=-5

∵ m is the rate of change

∴ The rate of change is -5

Substitute the value of m in the form of the linear relation

∴ y = -5 x + b

To find b substitute x and y in the equation by the coordinates of any points in the table, let us chose point (5 , 0)

∵ x = 5 and y = 0

∴ 0 = -5(5) + b

∴ 0 = -25 + b

- Add 25 to both sides

∴ 25 = b

∵ b represents the initial value

∴ The initial value is 25

The initial value: 25, rate of change: -5

Learn more:

You can learn more about the linear equation in brainly.com/question/4326955

#LearnwithBrainly

8 0
3 years ago
Round 2,173 to the nearest hundred
expeople1 [14]
The answer would be 2,200
7 0
2 years ago
Read 2 more answers
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