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3 years ago

(2x-10)(x+3) Simplify each expression

2 answers:

7 0

Use distributive property:
$(a+b)(c+d)+ac+ad+bc+bd$

$(2x-10)(x+3)=2x\cdot x+2x\cdot3-10\cdot x-10\cdot3\\\\=2x^2+6x-10x-30=2x^2-4x-30$

irga5000 [103]3 years ago

5 0

2x^2-4x-30 would be your answer

(2x−10)(x+3)
=(2x+−10)(x+3)
=(2x)(x)+(2x)(3)+(−10)(x)+(−10)(3)
=2x2+6x−10x−30
=2x2−4x−30

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The inverse of the function g(x)=x−65 can be written in the form g−1(x)=ax+b. What is the value of a?

Anna35 [415]

9514 1404 393

Answer:

a = 1

Step-by-step explanation:

The slope of the inverse of a linear function is the inverse of the slope of the original function.

The slope of g(x) is the coefficient of x: 1.

The inverse of 1 is 1/1 = 1.

The slope of the function g^-1(x) is 1, so a=1.

_____

Additional comment

g^-1(x) = x +65 . . . . . a=1; b=65

3 0

2 years ago

3x + 2 = -55 i need all the steps

Paha777 [63]

Answer:

-19

Step-by-step explanation:

3x+2 = -55

-2 -2

3x = -55-2

3x = -55+-2

3x = -57

/3 /3

x=-19

4 0

3 years ago

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sue, an experienced shipping clerk, can fill a ertain order 9 hours. Jim, a new clerk, needs 10 hours to do the same job. workin

GenaCL600 [577]

Let x be the time required to do the job when they work together.
1/x = 1/9 + 1/10 = 19/90
x = 90/19 = 4.7 hours

8 0

3 years ago

Which correctly renames 7/8 and 5/6 using a common denominator

OlgaM077 [116]

Common denominator is going to be 24
8=2*2*2
6=2*3
24=2*2*2*3

8 should be multiplied by 3
6 should be multiplied by 4
7/8=(7*3)/(8*3)=21/24
5/6=(5*4)/(6*4)=20/24
7/8=21/24
5/6=20/24

8 0

2 years ago

PLZ HELP ASAP! ILL MARK BRAINLEST!

Sav [38]

Question 1.) Factor completely $12x^{4}+ 6x^{3}+18x^{2}$

Since $6$ divides all the three terms of the equation, so we take $6$ common out from the equation.

i.e., $6(2x^{4}+ 1x^{3}+3x^{2})$

Now, since $x^{2}$ divides all the three terms of the equation, so we take $x^{2}$ common out from the equation.

i.e., $6x^{2}(2x^{2}+ 1x+3)$

Now, this cannot be factored further as $2x^{2}+ 1x+3$ is a quadratic equation and taking out discriminant of it is:

$D = (1)^2 - 4(2)(3)\\ \ \ = 1- 24\\ \ \ = -23$

Since, the discriminant is less than zero. Therefore, the factored form of the given equation : $12x^{4}+ 6x^{3}+18x^{2}$ is : $6x^{2}(2x^{2}+ 1x+3)$

Question 2.) $7x^{3}y+ 14x^{2} y^{3} - 7x^{2}y^{2}$

Since $7$ divides all the three terms of the equation, so we take $7$ common out from the equation.

i.e., $7(x^{3}y+ 2x^{2} y^{3} - x^{2}y^{2})$

Now, since $x^{2}y$ divides all the three terms of the equation, so we take $x^{2}y$ common out from the equation.

i.e., $7x^{2}y(x+ 2y^{2} - y)$

Therefore, the factored form of the given equation : $7x^{3}y+ 14x^{2} y^{3} - 7x^{2}y^{2}$ is : $7x^{2}y(x+ 2y^{2} - y)$

Question 3.) What is the Greatest Common Factor of $x^{6}$ and $x^{3}$ ?

The Greatest Common Factor of two numbers is the biggest number which divides both the given numbers completely.

Now, for the expressions $x^{6}$ and $x^{3}$ :

Since, $x^{3}$ divides both the expressions completely and it is the biggest expression which divides both the expressions.

Therefore, $x^{3}$ is the Greatest Common Factor of $x^{6}$ and $x^{3}$

7 0

3 years ago

Read 2 more answers