(1): "c0" was replaced by "c^0".
(2): Dot was discarded near "1.j". 1 more similar replacement(s)
Unauthorized use of the imaginary unit "i" or syntax error in complex arithmetic expression
Answer:
The height of the building is 
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
In the right triangle ABC
we have
substitute and solve for BC
Find the height of the building
The height of the building (h) is equal to
Answer:
$140.00
Step-by-step explanation:
22 students x $5.00 + $30
22 x $5.00 = $110.00
$110.00 + $30.00 = $140.00
Answer: By 9.1%
Step-by-step explanation:
The LCD is basically the LCM of the denoenator so
to find LCM of exg 6 and 21, find factors and group
6=2 and 3 (one 2 and one 3)
21=3 and 7 (one 3 and one 7)
lcm=2 and 3 and 7 (include 6 and 21 in the number) (one 2 and one 3 and one 7)
LCM≈LCD
so
17.
denomenators are 2 and x^2
2=2
x^2=x times x
lcm=2 times x times x=2x^2
18.
denomenators are 6 and 9
6=2 and 3
9=3 and 3
LCM=2 times 3 times 3=18
19.
denomenators are z and 7z
z=z
7z=7 and z
lcm=7 times z=7z
20.
denomenators are 5b and 7b^3c
5b=5 and b
7b^3c=7 times b times b times b times c
LCM=7 times 5 times b times b times b times c=7b^3c=7cb^3
21. denomenator=5 and x+2
5=5
x+2=x+2
LCM=5 times (x+2)=5(x+2)=5x+10
22. denomenators are ab and b^2c
ab=a time b
b^2c=b times b times c
LCM=a times b times b times c=ab^2c=acb^2
23. demonenators are m+n and m-n
m+n=m+n
m-n=m-n
LCM=(m+n)(m-n)=m^2-n^2
24.denoenators are k and k^2-2
k=k
k^2-2=k^2-2
LCM=k times (k^2-2)=k^3-2k
