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garik1379 [7]
2 years ago
13

Could use some help please

Mathematics
1 answer:
Helen [10]2 years ago
5 0

Answer:

Area of Square= 12*12= 144

Area of Circle= πr2

Radius= 12/2= 6

Area of Circle= 3.14*6*6 =113.04

Area of shaded region= 144- 113.04 = 30.96 = 31.0 (1 dp)

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What is the slope intercept form when m = 1/2 &amp; b = 89 ?<br> Helppppppppp
Zina [86]

Answer:

y = \frac{1}{2}x + 89

Step-by-step explanation:

slope-intercept form: y  = mx + b

y = (x , y)

x = (x , y)

m = slope = 1/2

b = y-intercept = 89

Plug in the corresponding numbers & variables to the corresponding variables:

y = (1/2)x + 89

y = \frac{1}{2}x + 89  is your answer.

~

5 0
3 years ago
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What is the slope of the line y = 6x + 3?<br> 3<br> -6<br> 6<br> -3
Nataly_w [17]

Answer:

the answer is 6

Step-by-step explanation:

slope = m

y = mx + c

m = 6

8 0
3 years ago
The following are the ages (years) of 5 people in a room:
Nat2105 [25]

Answer:

I think its 26 I would not swear it though

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3 years ago
Maths functions question
yarga [219]

Answer:

a)  OA = 1 unit

b)  OB = 3 units

c)  AB = √10 units

Step-by-step explanation:

<u>Given function</u>:

g(x)=2^x

<h3><u>Part (a)</u></h3>

Point A is the y-intercept of the exponential curve (so when x = 0).

To find the y-value of Point A, substitute x = 0 into the function:

\implies g(0)=2^0=1

Therefore, A (0, 1) so OA = 1 unit.

<h3><u>Part (b)</u></h3>

If BC = 8 units then the y-value of Point C is 8.

The find the x-value of Point C, set the function to 8 and solve for x:

\begin{aligned}f(x) & = 8 \\\implies 2^x & = 8\\2^x & = 2^3\\\implies x &= 3\end{aligned}

Therefore, C (3, 8) so Point B is (3, 0).  Therefore, OB = 3 units.

<h3><u>Part (c)</u></h3>

From parts (a) and (b):

  • A = (0, 1)
  • B = (3, 0)

To find the length of AB, use the distance between two points formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

\textsf{where }(x_1,y_1) \textsf{ and }(x_2,y_2)\:\textsf{are the two points.}

Therefore:

\implies \sf AB=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}

\implies \sf AB=\sqrt{(3-0)^2+(0-1)^2}

\implies \sf AB=\sqrt{(3)^2+(-1)^2}

\implies \sf AB=\sqrt{9+1}

\implies \sf AB=\sqrt{10}\:\:units

5 0
2 years ago
A farmer sells 8.8 kilograms of pears and apples at the farmer's market. 2 5 of this weight is pears, and the rest is apples. Ho
Snowcat [4.5K]

Answer:

5.28 kg

Step-by-step explanation:

A farmer sells 8.8 kilograms of pears and apples at the farmer's market and 2/5 of this weight is pears.

Since a fraction is a part of a whole, 1, then, the fraction repressing the weight of the apples is:

1 - 2/5 = 3/5

Therefore, the weight of apples is/

3 / 5 * 8.8 = 5.28 kg

She sold 5.28kg of apples at the farmer's market.

8 0
3 years ago
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