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3 years ago

Write cp and sp i bought a suit rs 5750.00 and sold it at rs 5890.00?

Mathematics

2 answers:

11111nata11111 [884]3 years ago

7 0

Answer:

The answers are,

Step-by-step explanation:

cp= rs 5750.00

sp= rs 5890.00

"cp" means Cost Price.

"sp" means Starting Price.

Levart [38]3 years ago

3 0

CP = Rs 5750.00

SP = Rs. 5890.00

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How many integers between 14 and 3,452 can be divided by 42 with a remainder of zero?

soldi70 [24.7K]

_______
42 I 3,452

82 with a remainder

There are 82 integers between 14 and 2452 that can be divided with a remainder of 0

4 0

3 years ago

A cylindrical swimming pool has a diameter of 16 feet and a height of 3 feet. How many gallons of water can the pool contain? Ar

kiruha [24]

Answer:

The pool can contain 4521.6 gallons of water.

Step-by-step explanation:

Given:

The diameter of the cylindrical swimming pool = 16 feet.

And the height of the cylindrical swimming pool = 3 feet.

(1 ft³ = 7.5 gallons)

Now, to find the gallons of water the pool can contain.

So, we find the radius first:

Radius (r) = $\frac{Diameter}{2}$ = $\frac{16}{2} =8\ feet.$

Height (h) = 3 feet.

Now, to get the volume of swimming pool which is cylindrical in shape by putting formula (using the value of π = 3.14):

$Volume=\pi r^2h$

$Volume=3.14\times 8^2\times 3$

$Volume=3.14\times 64\times 3$

$Volume=602.88\ feet^3.$

Thus, getting the volume of pool 602.88 feet³.

As, given 1 ft³ = 7.5 gallons.

Now, to get the gallons of water the pool can contain we multiply the volume of pool by 7.5:

$602.88\times 7.5$

$=4521.6\ gallons.$

Therefore, the pool can contain 4521.6 gallons of water.

7 0

3 years ago

(43 points) In the US, 85% of the population has Rh positive blood. Suppose we take a random sample of 6 persons and let Y denot

VladimirAG [237]

Answer:

a) Binomial distribution with parameters p=0.85 q=0.15 n=6

b) 62.29%

c) 2.38%

d) See explanation below

Step-by-step explanation:

We could model this situation with a binomial distribution

$P(6;k)=\binom{6}{k}p^kq^{6-k}$

where P(6;k) is the probability of finding exactly k people out of 6 with Rh positive, p is the probability of finding one person with Rh positive and q=(1-p) the probability of finding a person with no Rh.

$\bf P(Y=k)=\binom{6}{k}(0.85)^k(0.15)^{6-k}$

The probability that Y is less than 6 is

P(Y=0)+P(Y=1)+...+P(Y=5)

Let's compute each of these terms

$P(Y=0)=P(6;0)=\binom{6}{0}(0.85)^0(0.15)^{6}=1.139*10^{-5}$

$P(Y=1)=P(6;1)=\binom{6}{1}(0.85)^1(0.15)^{5}=0.0000387281$

$P(Y=2)=P(6;2)=\binom{6}{2}(0.85)^2(0.15)^{4}=0.005486484$

$P(Y=3)=P(6;3)=\binom{6}{3}(0.85)^3(0.15)^{3}=0.041453438$

$P(Y=4)=P(6;4)=\binom{6}{4}(0.85)^4(0.15)^{2}=0.176177109$

$P(Y=5)=P(6;5)=\binom{6}{5}(0.85)^5(0.15)^{1}=0.399334781$

and adding up these values we have that the probability that Y is less than 6 is

$\sum_{i=1}^{5}P(Y=i)=0.622850484\approx 0.6229=62.29\%$

In this case is a binomial distribution with n=200 instead of 6.

p and q remain the same.

The mean of this sample would be 85% of 200 = 170.

In a binomial distribution, the standard deviation is

$s = \sqrt{npq}$

In this case

$\sqrt{200(0.85)(0.15)}=5.05$

Let's approximate the distribution with a normal distribution with mean 170 and standard deviation 5.05

So, the approximate probability that there are fewer than 160 persons with Rh positive blood in a sample of 200 would be the area under the normal curve to the left of 160

(see picture attached)

We can compute that area with a computer and find it is

0.0238 or 2.38%

d) In order to approximate a binomial distribution with a normal distribution we need a large sample like the one taken in c).

In general, we can do this if the sample of size n the following inequalities hold:

$np\geq 5 \;and\;nq \geq 5$