Answer:
f(x) = 1/2x
Step-by-step explanation:
When x = -4 the output is -2
We are dividing by 2
When x = -2 the output is -1
f(x) = 1/2 x
Check when x = 2
f(2) = 1/2 (2) =1
C) 8 is the appropriate choice
4 dozen are made from 3 cups of flour, so twice that flour (6 cups) will produce twice the number of cookies, 8 dozen.
Let's begin by listing out the information given to us:
8 am
airplane #1: x = 80870 ft, v = -450 ft/ min
airplane #2: x = 5000 ft, v = 900ft/min
1.
We must note that the airplanes are moving at a constant speed. The equation for the airplanes is given by:

2.
We equate equations 1 & 2 to get the time both airlanes will be at the same elevation. We have:

3.
The elevation at that time (when the elevations of the two airplanes are the same) is given by substituting the value of time into equations 1 & 2. We have:
Answer:
For me
Step-by-step explanation:
I think it's A because x is unknown and per minutes meaning 50 times the x plus the 229