Question

Write the equation of the line that passes through the points (5,0) and (-6, -1).

Answer 1

Answer:

The equation in point-slope form is: $\mathbf{y=\frac{1}{11}x-\frac{5}{11} }$

Step-by-step explanation:

We need to find equation of line in point slope form that passes through points (5,0) and (-6, -1).

The general equation of point slope form is: $\mathbf{y-y_1=m(x-x_1)}$

where m is the slope of line.

We need to know Slope m

Finding Slope m

Finding Slope m using formula: $Slope=\frac{y_2-y_1}{x_2-x_1}$

We have $x_1=5, y_1=0, x_2=-6 \ and \ y_2=-1$

Putting values and finding slope

$Slope=\frac{-1-0}{-6-(5)}\\Slope=\frac{-1}{-6-5}\\Slope=\frac{-1}{-11}\\Slope=\frac{1}{11}$

So , slope m is: $\mathbf{m=\frac{1}{11}}$

Using point (5,0) and slope m =1/22 the equation of point-slope form is:

$y-y_1=m(x-x_1)\\y-0=\frac{1}{11} (x-5)\\y=\frac{1}{11}x-\frac{5}{11}$

So, the equation in point-slope form is: $\mathbf{y=\frac{1}{11}x-\frac{5}{11} }$