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3 years ago

Solve the linear equation

Mathematics

1 answer:

Nikolay [14]3 years ago

4 0

Answer:

Step-by-step explanation:

x/2-3x/4+5x/8=9

Or,(4*x-2*3x+5x)/8=9. (taking LCM)

Or, (4x-6x+5x)/8=9

Or, 3x=9*8

Or, x = 72/3

so, x=24.

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You must write your answer in fully simplified form.<br>2t= -12

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Answer:

t=-6

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1 year ago

A teacher keeps track of the number of students that participate at least three times in an optional study session each year. He

Anastasy [175]

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It is not C got it wrong.

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2 years ago

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Translate point R located at (-6,-8) -4 in the x-direction and -2 in th y-direction

Troyanec [42]

((-6-4),(-8-2))

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3 years ago

The range of y = - 32x ^ 2 + 90x + 3

mariarad [96]

Given:

The given function is:

$y=-32x^2+90x+3$

To find:

The range of the given function.

Solution:

We have,

$y=-32x^2+90x+3$

It is a quadratic function because the highest power of the variable x is 2.

Here, the leading coefficient is -32 which is negative. So, the graph of the given function is a downward parabola.

If a quadratic function is $f(x)=ax^2+bx+c$ , then the vertex of the quadratic function is:

$Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)$

In the given function, $a=-32,b=90,c=3$ .

$\dfrac{-b}{2a}=\dfrac{-90}{2(-32)}$

$\dfrac{-b}{2a}=\dfrac{-90}{-64}$

$\dfrac{-b}{2a}=\dfrac{45}{32}$

The value of the given function at $x=\dfrac{45}{32}$ is:

$y=-32(\dfrac{45}{32})^2+90(\dfrac{45}{32})+3$

$y=\dfrac{2121}{32}$

The vertex of the given downward parabola is $\left(\dfrac{45}{32},\dfrac{2121}{32}\right)$ . It means the maximum value of the function is $y=\dfrac{2121}{32}$ . So,

$Range=\left\{y|y\leq \dfrac{2121}{32}\right\}$

$Range=\left(-\infty, \dfrac{2121}{32}\right ]$

Therefore, the range of the given function is $\left (-\infty, \dfrac{2121}{32}\right ]$ .

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3 years ago

Using 6 as a denominator, what fraction completes the following equation: 1 − 1/3 = ? a. 3/6 c. 5/6 b. 4/6 d. 2/6

nika2105 [10]

C
because of explain

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3 years ago