Answer:
p=28
Step-by-step explanation:
5p=140
To to find the value of p divide both sides by 5 (5p/5 and 140/5)
p=28!
The volume of the cylinder in terms of π is 18,095.5736 square yards,
the volume of the cylinder by using π equals 3.14 is 18.086.4 square yards.
Step-by-step explanation:
Step 1; The volume of any cylinder is given by π times the product of the square of the radius (r²) and the height (h). The given cylinder has a radius of 12 yards and a height of 40 yards.
The volume of any cylinder = π × r² × h.
Step 2; The value of π equals 3.14159263588. So substituting this value in the equation to calculate the volume we get
The volume of the given cylinder = 3.14159263588 × 12² × 40 = 18,095.5736 square yards.
Step 3; If we substitute the value of π as 3.14 in the equation to calculate the volume, we get
The volume of the given cylinder = 3.14 × 12² × 40 = 18.086.4 square yards.
(5-2/x)/4-3/x^2
after simplifying these
(5x-2)/x(4x^2-3)/x^2
x(5x-2)/(4x^2-3)
5x^2-2x/4x^2-3
now u can solve it
Answer:
unreadable score = 35
Step-by-step explanation:
We are trying to find the score of one exam that is no longer readable, let's give that score the name "x". we can also give the addition of the rest of 9 readable s scores the letter "R".
There are two things we know, and for which we are going to create equations containing the unknowns "x", and "R":
1) The mean score of ALL exams (including the unreadable one) is 80
so the equation to represent this statement is:
mean of ALL exams = 80
By writing the mean of ALL scores (as the total of all scores added including "x") we can re-write the equation as:
since the mean is the addition of all values divided the total number of exams.
in a similar way we can write what the mean of just the readable exams is:
(notice that this time we don't include the grade x in the addition, and we divide by 9 instead of 10 because only 9 exams are being considered for this mean.
Based on the equation above, we can find what "R" is by multiplying both sides by 9:
Therefore we can now use this value of R in the very first equation we created, and solve for "x":
