Answer:
Step-by-step explanation:
Hello!
The objective is to determine if there is a linear association between the price of a mountain bike (Y) and it's the weight (X).
a.
Looking at the Scatterplot the data is dispersed in all quadrants of the graph, at first glance there seems to be some kind of functional relationship between the price and weight of mountain bike bicycles. If you are not too strict maybe there could be a slight negative relationship between them.
b.
The linear regression model is E(Yi)= α + βXi
To find the regression model for this particular set of variables you have to estimate the intercept and the slope.
a= Y[bar] - bX[bar] = 1961.40 $
b=
= -42.99 $/LB
^Yi= 1961.40 - 42.99Xi
$ 1961.40 is the estimated value of the average price if the weight of the mountain bike is zero. (It has no contextual sense)
-42.99 $/LB is the modification of the estimated average price every time the weight of the mountain bike.
c.
In this item, you need yo obtain a value of price for a given value of weight. To do so all you have to do is replace the value on the estimated regression model:
^Y/X=3232= 1961.40 - 42.99*32= $585.72
I hope it helps!
Answer:
<h2>x = 7</h2>
Step-by-step explanation:

<u>Multiply the terms in the bracket</u>
We have
- 3x - 14 - 5x = - 70
- 8x - 14 = - 70
Using the addition property, add 14 to both sides
That's
- 8x + 14 - 14 = - 70 + 14
- 8x = - 56
<u>Divide both sides by - 8</u>
That's
<h3>

</h3>
We have the final answer as
<h3>x = 7</h3>
Hope this helps you
Convert 20 min to hrs: 20/60 = 1/3 hr
Let t = time on the bikethent-(1/3) = time on the bus
Write a dist equation Dist = speed * time:Bike dist + bus dist = 26 mi6t + 30[t-(1/3)] = 26:6t + 30t - 10 = 2636t = 26 + 1036t = 36t = 1 hr on the bike
6 mph for 1 h = 6 mi from house to the bus station
Check solution by finding the distance6(1) + 30(2/3) =6 + 20 = 26 mi
Answer:
Step-by-step explanation:
Answer:
the answer is step 2 I hope it's help