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1 year ago

8

-If the circumference of a circle is 20T units, what is its area?

1 answer:

Anna71 [15]1 year ago

5 0

The answer would be 31.83! <3

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Can you please help you have to type in a number her is the screenshot

lyudmila [28]

Answer:

Step-by-step explanation:

Rate = (20½ pounds)/(4 hours) = (5⅛ pounds)/hour

9 hours × (5⅛ pounds)/hour = 46⅛ pounds

4 0

2 years ago

Cloud [144]

What is this about because I’m confuse

4 0

2 years ago

I WILL MARK BRAINLIEST

vagabundo [1.1K]

Answer:

$\frac{81}{m^7}$

Step-by-step explanation:

We have a certain expression and are asked to find its equivalent with the answers provided :

$(3m^{-4} )^3(3m^5)$

Remove the parenthesis around 3m^5 :

$(3m^{-4} )^3*3m^5$

Do the exponent rule for outside and inside exponent parenthesis :

$(3m^{-4*3} )$

$3^3m^{-12} *3m^5$

Apply addition exponent rule :

$m^{-12} *3^{3+1} m^5$

Add :

$m^{-12} *3^4m^5$

Apply the addition rule for -12 + 5 :

$3^{4} m^{-7}$

Apply negative exponent rule for m^-7 :

$3^4*\frac{1}{m^7}$

Multiply the fractions :

$\frac{1*3^4}{m^7}$

$\frac{81}{m^7}$

3 0

2 years ago

8x - 5 - 6 - 7 <br> Can someone solve this

Iteru [2.4K]

Answer:

8x-18

Step-by-step explanation:

ggv dcbbccc. bvvccv. vccbv. vvvvv

4 0

2 years ago

Read 2 more answers

Given the following three points, find by the hand the quadratic function they represent (0,6, (2,16, (3,33)

Lisa [10]

Answer:

$f(x) = 4x^2 - 3x + 6$

Step-by-step explanation:

Quadratic function is given as $f(x) = ax^2 + bx + c$

Let's find a, b and c:

Substituting (0, 6):

$6 = a(0)^2 + b(0) + c$

$6 = 0 + 0 + c$

$c = 6$

Now that we know the value of c, let's derive 2 system of equations we would use to solve for a and b simultaneously as follows.

Substituting (2, 16), and c = 6

$f(x) = ax^2 + bx + c$

$16 = a(2)^2 + b(2) + 6$

$16 = 4a + 2b + 6$

$16 - 6 = 4a + 2b + 6 - 6$

$10 = 4a + 2b$

$10 = 2(2a + b)$

$\frac{10}{2} = \frac{2(2a + b)}{2}$

$5 = 2a + b$

$2a + b = 5$ => (Equation 1)

Substituting (3, 33), and c = 6

$f(x) = ax^2 + bx + x$

$33 = a(3)^2 + b(3) + 6$

$33 = 9a + 3b + 6$

$33 - 6 = 9a + 3b + 6 - 6$

$27 = 9a + 3b$

$27 = 3(3a + b)$

$\frac{27}{3} = \frac{3(3a + b)}{3}$

$9 = 3a + b$

$3a + b = 9$ => (Equation 2)

Subtract equation 1 from equation 2 to solve simultaneously for a and b.

$3a + b = 9$

$2a + b = 5$

$a = 4$

Replace a with 4 in equation 2.

$2a + b = 5$

$2(4) + b = 5$

$8 + b = 5$

$8 + b - 8 = 5 - 8$

$b = -3$

The quadratic function that represents the given 3 points would be as follows:

$f(x) = ax^2 + bx + c$

$f(x) = (4)x^2 + (-3)x + 6$

$f(x) = 4x^2 - 3x + 6$

6 0

3 years ago