Here
45 :72 = 40:p
Or 45/72=40/p
Or 45p = 72*40
Or p = 2880/45
Or p= 64
Thank you
Ayanas
The set of natural numbers greater than or equal to 6 will be 6, 7, 8, 9, 10, ....
<h3>How to illustrate the information?</h3>
It should be noted that the first information is about the set of natural numbers greater than or equal to 6. Therefore, they will be 6 and above.
It should be noted that the descriptive form simply states in words the elements that are in a set. It is the verbal description of the elements in the set. It is the determination of the elements that belong to a set and those that doesn't.
Also, the way that a set is described is known as the roster form. In this case, the contents of a set can be described by listing the elements that are in the set which are separated by a comma inside the bracket.
Also, the roster form: (5, 7, 9, 11) indicates odd natural numbers. The numbers that are given are odd.
Learn more about numbers on:
brainly.com/question/15653848
#SPJ1
Answer:
60
Step-by-step explanation:
We have to find least common denominator for these fractions or we just have to find the least common multiple for 15, 6 and 4
In order to find the least common multiple, we have to represent these numbers as factors of prime numbers:
15 = 3 * 5
6 = 2 * 3
4 = 2 * 2
Least common multiples will be common factors (considering that there are no more than of them in other numbers) and the uncommon factors. Then, we can write that:
2 * 2 * 3 * 5 = 60 (there are two 2's, one common 3 and an uncommon 5)
The denominator will be 60 for the least common multiples.
6/4 = 1.5 liters of pain per brother
Answer:
$3355
Step-by-step explanation:
Since the job offers starting salary of $2200 and monthly raise of $105 during his first year of training.
∴ a = 2200 and d = 105
Since the general form of A.P is,
a, a + d, a + 2d, a + 3d, .............
Where, is the last term of A.P or his monthly salary at the end of his training and n is the number of terms in a series.
So, the A.P is:
2200, 2200 + 105, 2200 + 2(105) .........
2200, 2305, 2410 ............
Since there is 12 month in a year therefore, n = 12.
. = 2200 + ( 12 - 1) × 105
= 2200 + 11 × 105
= 2200 + 1155
= 3355
∴ . = 3355
So the monthly salary of Jose at the end of his training is 3355$.
