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Anna11 [10]
3 years ago
12

$0.30 per ounce, how much would 2 lb cost?

Mathematics
1 answer:
natali 33 [55]3 years ago
7 0
Well 16 ounces equals a pound. So 16+16=32 ounces.
So 32 ounces times $0.30 equals 9.6.
So 2 lbs should cost $9.6.
Hope this helps.
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J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
3 years ago
The standard form of y = -x + 2 is x + y = 2.<br> Group of answer choices<br><br> True<br><br> False
Ipatiy [6.2K]
The answer to this is true
6 0
3 years ago
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Rufina [12.5K]
I dont' know im soooo sorry for not knowing

3 0
3 years ago
EFGH is a parallelogram. Find the measure of EG.
gayaneshka [121]

Answer: 64

Step-by-step explanation:

If EFGH is a parallelogram, its diagonals bisect each other meaning EJ and JG are congruent.

EJ = JG

4w + 4 = 2w + 18

Subtract 2w from both sides

2w + 4 = 18

Subtract 4 from both sides

2w = 14

Divide both sides by 2

w = 7

EG = EJ + JG

EG = 4w + 4 + 2w + 18

EG = 6w + 22

Now that we know what 'w' is, we can substitute it for 7

EG = 6 (7) + 22

EG = 42 + 22 = 64

The measure of EG is 64.

Hope that helped!

7 0
3 years ago
In the triangle below, what ratio represents cot Y?
arsen [322]
TanY=y/x

cotY=1/tanY

cotY=x/y
7 0
3 years ago
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