I think it is C for the answer yu have
Side of the original square. x2 x<span>. Square </span>has all<span> sides the same </span>length x<span> ... </span>2<span>. Our Solution. Example 3. The </span>length<span> of a </span>rectangle<span> is </span>4<span> ft greater than the </span>width<span>. If each </span>dimension<span> is ... (x+ 3)(x+ 7) =</span>x<span>(x+ </span>4<span>) +33 Set up equation, </span>length times width<span> is area .... </span>5<span>) </span>6 x 10<span>. </span>6<span>) 20 ft </span>x<span> 35 ft. 7) </span>6<span>” </span>x 6<span>”. </span>8<span>) </span>6<span> yd </span>x<span> 7 yd. </span>9<span>) </span>4<span> ft </span>x<span> 12 ft. </span>10<span>) 1.54 in.</span>
The answer is: " 112 bricks " .
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Explanation:
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Volume of each brick: (14 in) * (8 in) * (5 in) = 560 in³ .
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Now:
16800 in³ ÷ 560 in³ = 16800 ÷ 560 = 1680 ÷ 56 = 112.
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