I think it’s 138
Hope this helps
I think 104,000 is the answer because when 26,000 is double it's 52,000 so I doubled 52,000 and 104,000 is what I got.
Answer:
The required form is
.
Step-by-step explanation:
Consider the provided quadratic function.
![y=x^2 + 14x + 40](https://tex.z-dn.net/?f=y%3Dx%5E2%20%2B%2014x%20%2B%2040)
We need to put the equation into the form ![y = (x - h )^2 + k](https://tex.z-dn.net/?f=y%20%3D%20%28x%20-%20h%20%29%5E2%20%2B%20k)
Add and subtract 49 in order to make the above function a perfect square.
![y=x^2 + 14x+49-49 + 40](https://tex.z-dn.net/?f=y%3Dx%5E2%20%2B%2014x%2B49-49%20%2B%2040)
![y=x^2 + 14x+7^2-49 + 40](https://tex.z-dn.net/?f=y%3Dx%5E2%20%2B%2014x%2B7%5E2-49%20%2B%2040)
![y=(x+7)^2-49 + 40](https://tex.z-dn.net/?f=y%3D%28x%2B7%29%5E2-49%20%2B%2040)
![y=(x+7)^2-9](https://tex.z-dn.net/?f=y%3D%28x%2B7%29%5E2-9)
Hence, the required form is
.
Answer:
see explanation
Step-by-step explanation:
Using the rules of exponents
= ![\frac{1}{a^{m} }](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Ba%5E%7Bm%7D%20%7D)
= ![\sqrt[n]{a^{m} }](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5E%7Bm%7D%20%7D)
Given
![y^{-\frac{a}{b} }](https://tex.z-dn.net/?f=y%5E%7B-%5Cfrac%7Ba%7D%7Bb%7D%20%7D)
= ![\frac{1}{y^{\frac{a}{b} } }](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7By%5E%7B%5Cfrac%7Ba%7D%7Bb%7D%20%7D%20%7D)
= ![\frac{1}{\sqrt[b]{y^{a} } }](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%5Bb%5D%7By%5E%7Ba%7D%20%7D%20%7D)