What happens after coral is bleached?

What are limitations of a conclusion? I am doing a science lab write-up and under the conclusion it asks for limitations of the

enyata [817]

I believe it means the imitations on what you did what were you not able to do to the object. I'm not too sure but I believe that's what it means. I hope I was able to help

5 0

3 years ago

Lithium (Li) has 3 electrons. How many shells does an atom of Li have?

Liula [17]

She has 3 I just did that test. Have a good day

8 0

3 years ago

Read 2 more answers

How many grams of an 8% w/w progesterone gel must be mixed with 1.45 g of a 4% w/w progesterone gel to prepare a 5.5% w/w gel?

Nimfa-mama [501]

Answer: 0.87 g of an 8% w/w progesterone gel must be mixed with 1.45 g of a 4% w/w progesterone gel to prepare a 5.5% w/w gel.

Explanation:

According to the dilution law,

$C_1w_1+C_2w_2=C_3w_3$

where,

$C_1$ = concentration of ist progesterone gel = 8%w/w

$w_1$ = weight of ist progesterone gel = x g

$C_2$ = concentration of another progesterone gel = 4% w/w

$w_2$ = weight of another progesterone gel = 1.45 g

$C_3$ = concentration of resulting progesterone gel = 5.5%w/w

$w_3$ = weight of resulting progesterone gel = (x+1.45) g

$8\times x+4\times 1.45=5.5\times (x+1.45)$

$x=0.87$

Thus 0.87 g of an 8% w/w progesterone gel must be mixed with 1.45 g of a 4% w/w progesterone gel to prepare a 5.5% w/w gel.

4 0

4 years ago

12. How many molecules of glucose, C6H12O6, are present in a 152 g sample

ELEN [110]

Q.No. 12:

Answer:

5.08 × 10²³ Glucose Molecules

Solution:

Data Given:

Mass of Glucose = 152 g

M.Mass of Glucose = 180.156 g.mol⁻¹

Step 1: Calculate Moles of Glucose as,

Moles = Mass ÷ M.Mass

Putting values,

Moles = 152 g ÷ 180.156 g.mol⁻¹

Moles = 0.8437 mol

Step 2: Calculate number of Glucose Molecules,

As 1 mole of any substance contains 6.022 × 10²³ particles (Avogadro's Number) then the relation for Moles and Number of glucose molecules can be written as,

Moles = Number of Glucose Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹

Solving for Number of Glucose Molecules,

Number of Glucose Molecules = Moles × 6.022 × 10²³ Molecules.mol⁻¹

Putting value of moles,

Number of Glucose Molecules = 0.8437 mol × 6.022 × 10²³ Atoms.mol⁻¹

Number of Glucose Molecules = 5.08 × 10²³ Glucose Molecules

______________________________________________

Q.No. 12: (A)

Answer:

3.04 × 10²⁴ Carbon Atoms

Solution:

The molecular formula of Glucose is C₆H₁₂O₆. This specifies that there are six carbon atoms in one molecule of Glucose.

Hence, when,

1 molecule of Glucose contain = 6 atoms of Carbon

Then,

5.08 × 10²³ Glucose Molecules will contain = X atoms of Carbon

Solving for X,

X = 5.08 × 10²³ molecules × 6 atoms / 1 molecule

X = 3.04 × 10²⁴ Carbon Atoms

______________________________________________

Q.No. 12: (B)

Answer:

1.22 × 10²⁵ Atoms in total

Solution:

The molecular formula of Glucose is C₆H₁₂O₆. This specifies that there are 6 carbon atoms, 12 hydrogen atoms and 6 oxygen atoms in one molecule of Glucose. So, there are 24 atoms in one molecule of glucose

Hence, when,

1 molecule of Glucose contain = 24 atoms

Then,

5.08 × 10²³ Glucose Molecules will contain = X atoms

Solving for X,

X = 5.08 × 10²³ molecules × 24 atoms / 1 molecule

X = 1.22 × 10²⁵ Atoms in total

______________________________________________

Q. No. 13

Answer:

1061.81 g of Aluminium

Solution:

Data Given:

Number of F.Units = 2.37 × 10²⁵

A.Mass of Aluminium = 26.98 g.mol⁻¹

Mass of Aluminium = ?

Step 1: Calculate Moles of Aluminium,

Moles = Number of F.Units ÷ 6.022 × 10²³ F.Units.mol⁻¹

Putting value,

Moles = 2.37 × 10²⁵ F.Units ÷ 6.022 × 10²³ F.Units.mol⁻¹

Moles = 39.35 mol

Step 2: Calculate Mass of Aluminium as:

Moles = Mass ÷ A.Mass

Solving for Mass,

Mass = Moles × A.Mass

Putting values,

Mass = 39.35 mol × 26.98 g.mol⁻¹

Mass = 1061.81 g of Aluminium

8 0

3 years ago

What type of substances is filtration useful for seperating? Give me an example.

Butoxors [25]

Filtration is useful for separating sediments that are carried in water for easy drinking without the risk of disease - an example of this is a water purifier

4 0

4 years ago