Answer:
0.474 moles of C₆H₆OS
Explanation:
Step 1: Write the balanced equation
2 C₆H₆OS + 11 O₂ ⇒ 12 CO + 6 H₂O + 2 SO₃
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of C₆H₆OS to SO₃ is 2:2.
Step 3: Calculate the moles of C₆H₆OS reacted if 0.474 moles of SO₃ are produced
We will use the previously established molar ratio.
0.474 mol SO₃ × 2 mol C₆H₆OS/2 mol SO₃ = 0.474 mol C₆H₆OS
According to Arrhenius concept a base is one which can donate hydroxide ion in its aqueous solution.
Here NaOH is a base as it can donate OH-.
As NaOH is a strong base it will have very high dissociation constant.
Due to high dissociation constant if will almost completely dissociate into sodium ions and hydroxide ions.
Thus in a solution of NaOH we will expect the following two ions
Na^{+} + OH^{-}[/tex]
Answer:
Atom is a particle that defines a chemical element, and is normally surrounded by 2 electrons.
Also, how do you that font ?
Answer:
7 moles
Explanation:
Given data:
Moles of hydrogen = 7 mol
Moles of water formed = ?
Solution:
Chemical equation:
2H₂ + O₂ → 2H₂O
Now we will compare the moles of water with hydrogen from balance chemical equation:
H₂ : H₂O
2 : 2
7 : 7
So in the presence of excess oxygen and 7 moles of hydrogen seven number of moles of water produced.
Answer:
moles in 0.250 g of h20 is 1.349x10^-2