Answer:
0.0171
0.89158
Step-by-step explanation:
Given :
μ = 60
Standard deviation , σ = 17
The probability that a randomly chosen score is greater than 96;
P(Z > Zscore)
Zscore = (score, x - μ) / σ
Zscore = (96 - 60) / 17 = 2.118
P(Z > 2.118) = 1 - P(Z < 2.118) = 1 - 0.9829 = 0.0171
The probability that a randomly chosen score is less than 81;
P(Z < Zscore)
Zscore = (score, x - μ) / σ
Zscore = (81 - 60) / 17 = 1.235
P(Z < 1.235) = 0.89158
