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Mathematics

1 answer:

Alex17521 [72]3 years ago

3 0

18 1/4 pieces she will have now
:)

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What is 4 1/3 × 2 3/5? express it in lowest terms

soldier1979 [14.2K]

We have,

$4\dfrac{1}{3}\cdot2\dfrac{3}{5}=\dfrac{13}{3}\cdot\dfrac{13}{5}=\dfrac{13\cdot13}{3\cdot5}=\dfrac{169}{15}=\boxed{11.2\bar{6}}$

To express periodic number calculated we use:

$x=11.2\bar{6}\\10x = 112.\bar{6}\\100x=1126.\bar{6}\\90x=100x-10x\Longrightarrow90x=1126.\bar6-112.\bar6\\90x=1014\\x=\dfrac{1014}{90}=\boxed{11\dfrac{24}{90}}$

Hope this helps.

r3t40

3 0

3 years ago

ExtremeBDS [4]

It’s 13.1 ft I know cause I did the math all the way it’s 13.1 so yeah

5 0

3 years ago

Rewrite sqr-100 +26 in complex number notation

Morgarella [4.7K]

Answer:

26 + 10i is your answer.

8 0

3 years ago

Audrey, an astronomer is searching for extra-solar planets using the technique of relativistic lensing. Though there are believe

Stolb23 [73]

Answer:

Step-by-step explanation:

The model $N (t)$ , the number of planets found up to time $t$ , as a Poisson process. So, the $N (t)$ has distribution of Poison distribution with parameter $(\lambda t)$

The mean for a month is, $\lambda = \frac{1}{3}$ per month

$E[N(t)]= \lambda t\\\\=\frac{1}{3}(24)\\\\=8$

(Here. t = 24)

For Poisson process mean and variance are same,

$Var[N (t)]= Var[N(24)]\\= E [N (24)]\\=8$

(Poisson distribution mean and variance equal)

The standard deviation of the number of planets is,

$\sigma( 24 )] =\sqrt{Var[ N(24)]}=\sqrt{8}= 2.828$

For the Poisson process the intervals between events(finding a new planet) have independent exponential distribution with parameter $\lambda$ . The sum of $K$ of these independent exponential has distribution Gamma $(K, \lambda)$ .