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3 years ago

Simplify (23)^–2 genuinely confused

Mathematics

1 answer:

statuscvo [17]3 years ago

7 0

Answer:

1/529

Step-by-step explanation:

$23^{-2}\\\\\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}\\23^{-2}=\frac{1}{23^2}\\\\23^2=529\\\\=\frac{1}{529}$

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the midpoint of PQ is R. R has coordinates (-3,2,-1) and P has coordinates (4,-6,-6). What are coordinates of Q?

vlabodo [156]

Point Q would have the coordinates of (-10, 10, 4)

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3 years ago

Among the eighth-graders in Michael's school, 70% have siblings. The eighth-grade class is 5/6 the size of the seventh-grade cla

trapecia [35]

Answer:

D. 192

Step-by-step explanation:

This problem involves a few steps. First, you need to determine how many eighth graders you have given that 112 represent 70% of the total number of eighth graders. You can solve this using a proportion:

$\frac{70}{100}=\frac{112}{x}$

Cross-multiply and divide: 70x = 11200 or 70x/70 = 11200/70 or x = 160

Since there are 160 total eighth graders and this is $\frac{5}{6}$ of the amount of seventh graders, we can set up an equation to solve for the total amount of seventh graders:

160 = $\frac{5}{6}$ x

Multiply by the reciprocal of your fraction on both sides:

$\frac{6}{5}$ x 160 = $\frac{5}{6}$ x ( $\frac{6}{5}$ )

Solve for x: x = 192 seventh graders

5 0

3 years ago

I need help can somebody help me please???

stich3 [128]

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3 0

3 years ago

What is the factored form of the expression? k2 – 9h2

VARVARA [1.3K]

The factored form of this expression would be :

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3 years ago

Read 2 more answers

A stadium has 50,000 seats. Seats sell for $28 in Section A, $24 in Section B, and $20 in Section C. The number of seats in Sect

Pepsi [2]

Answer:

Section A holds 25,000 seats, section B holds 14,500 seats and section C holds 10,500 seats.

Step-by-step explanation:

From the information given you can write the following equations:

A+B+C=50,000 (1)

28A+24B+20C=1,258,000 (2)

A=B+C (3)

A= number of seats in section A

B= number of seats in section B

C= number of seats in section C

You can replace (3) in (1) and (2) to get two equations:

B+C+B+C=50,000

2B+2C=50000

28(B+C)+24B+20C=1,258,000

28B+24B+28C+20C=1,258,000

52B+48C=1,258,000

The two equations are:

2B+2C=50000 (4)

52B+48C=1,258,000 (5)

You can isolate B in (4):

2B=50,000-2C

B=(50,000/2)-(2C/2)

B=25,000-C

Now, you can replace B in (5):

52(25,000-C)+48C=1,258,000

1,300,000-52C+48C=1,258,000

1,300,000-1,258,000=4C

42,000=4C

C=42,000/4

C=10,500

Now, you can replace the value of C in B=25,000-C:

B=25,000-10,500

B=14,500

Finally, you can replace the values of B and C in A=B+C to find A:

A=14,500+10,500

A=25,000

According to this, the answer is that section A holds 25,000 seats, section B holds 14,500 and section C holds 10,500.

6 0

3 years ago