Answer:
They are at the same height at 1.13 seconds.
Step-by-step explanation:
Remark
The rockets are at the same height when f(x) = g(x) [see below] are the same. So you can equate them.
Givens
f(x) = - 16x^2 + 74x + 9
g(x) = -16x^2 + 82x I have changed this so you don't have 2 f(x)s
Solution
- f(x) = g(x)
- -16x^2 + 74x + 9 = -16x^2 + 82x Add: 16x^2 to both sides
- -16x^2+16x^2+74x + 9 = -16x^2+16x^2 + 82x Combine terms
- 74x + 9 = 82x Subtract 74x from both sides
- 74x - 74x + 9 = 82x - 74x Combine
- 9 = 8x Divide by 8
- 9/8 = 8x/8
- x = 1 1/8 Convert to decimal
- x = 1.125
- x = 1.13 [rounded]
Answer:
18 plastic propellers, 18 Bug Antenna, 24 moose antlers,
Step-by-step explanation:
When we multiply our total sum of 60 by certain decimal values by converting the factions to decimals we can get each type of hats count.
1/3 works out to be 0.30
60×0.3 = 18
2/5 works out to be 0.40
60×0.4 = 24
To find out the remaining amount that is plastic propellers you subtract the added hats and the total value.
60 - (18 + 24)
60 - 42
18
The given in the problem above is an arithmetic sequence with the first term equal to 4 and the common difference is 5. To determine the number of seats on row 23, use the formula, an = a1 + (n - 1) d
Solving for the 23rd term, an = 4 + (22) 5 = 114 seats
Therefore, the answer is there are 114 seats on the 23rd row.
Welcome Bby (;
513/2=256.5
which means 256 and 257 are the answers
Use trigonometry.
sinQ = 14/50 = 0.28
-> angle Q = sin^-1(0.28) = approx 16 degrees
-> cosQ = A/H -> cos16 = PQ/50
=> PQ = 50*cos16 = approx 48.06
So yea.
