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3 years ago

Simplify (23)^–2 genuinely confused

Mathematics

1 answer:

statuscvo [17]3 years ago

7 0

Answer:

1/529

Step-by-step explanation:

$23^{-2}\\\\\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}\\23^{-2}=\frac{1}{23^2}\\\\23^2=529\\\\=\frac{1}{529}$

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damaskus [11]

Answer:

0.6472 = 64.72% probability that a randomly selected page does not need to be retyped.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Poisson distribution with an average of three errors per page

This means that $\mu = 3$

What is the probability that a randomly selected page does not need to be retyped?

Probability of at most 3 errors, so:

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-3}*3^{0}}{(0)!} = 0.0498$

$P(X = 1) = \frac{e^{-3}*3^{1}}{(1)!} = 0.1494$

$P(X = 2) = \frac{e^{-3}*3^{2}}{(2)!} = 0.2240$

$P(X = 3) = \frac{e^{-3}*3^{3}}{(3)!} = 0.2240$

Then

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0498 + 0.1494 + 0.2240 + 0.2240 = 0.6472$

0.6472 = 64.72% probability that a randomly selected page does not need to be retyped.

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pentagon [3]

Answer:

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Step-by-step explanation:

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Let x=2 then, Y=(3×2)-1=5

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Let x=0 then Y=(3×0)-1=-1

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3 years ago

Find the sum of the infinite series, if it exists. 100+20+4+… And please show work

Vedmedyk [2.9K]

Answer:

Step-by-step explanation:

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3 years ago

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jekas [21]

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3 years ago