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Oksanka [162]
3 years ago
12

WILL MARK BRAINLIEST IF CORRECT! PLS HELP

Mathematics
1 answer:
Elanso [62]3 years ago
4 0

Answer:

y^{\frac{2}{5}}

Step-by-step explanation:

2 - \frac{4}{5} = \frac{2*5}{1*5}-\frac{4}{5}\\\\ = \frac{10}{5}-\frac{4}{5}\\\\= \frac{6}{5}

\frac{a^{m}}{a^{n}}=a^{m-n}\\\\

\sqrt[3]{\frac{y^{2}}{y^{\frac{4}{5}}}} =\sqrt[3]{y^({2-\frac{4}{5})}} \\\\=\sqrt[3]{y^{\frac{6}{5}}}\\\\=(y^{\frac{6}{5}})^{\frac{1}{3}} \\\\=y^{\frac{6}{5}*\frac{1}{3}}\\\\= y^{\frac{2}{5}}

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divide it by 2

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3 years ago
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svetoff [14.1K]
The parameter of a rectangle can be alculated using the following rule:
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3 years ago
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