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Oksanka [162]
3 years ago
12

WILL MARK BRAINLIEST IF CORRECT! PLS HELP

Mathematics
1 answer:
Elanso [62]3 years ago
4 0

Answer:

y^{\frac{2}{5}}

Step-by-step explanation:

2 - \frac{4}{5} = \frac{2*5}{1*5}-\frac{4}{5}\\\\ = \frac{10}{5}-\frac{4}{5}\\\\= \frac{6}{5}

\frac{a^{m}}{a^{n}}=a^{m-n}\\\\

\sqrt[3]{\frac{y^{2}}{y^{\frac{4}{5}}}} =\sqrt[3]{y^({2-\frac{4}{5})}} \\\\=\sqrt[3]{y^{\frac{6}{5}}}\\\\=(y^{\frac{6}{5}})^{\frac{1}{3}} \\\\=y^{\frac{6}{5}*\frac{1}{3}}\\\\= y^{\frac{2}{5}}

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A line passes through the origin and (3, 6). Which
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6 0
3 years ago
David kicks a soccer ball off the ground and in the air, with an initial velocity of 35 feet per second. Using the formula H(t)
sesenic [268]

Answer:

Step-by-step explanation:

The function for this problem is: h(t) = -16(t)^2 + vt + s h= the height t= time v= velocity s= starting height With the information given, we know that the starting height is 0, since it was from the ground, and the velocity of the ball is 35 feet per second. Inserting the these information into the equation, we get: h(t) = -16(t)^2 + 35t Now the question asks to find the maximum height. It can be done by using a grapher to graph the maximum of the parabola. It could also be done by finding the vertex, which would be the maximum, of the graph by using x= -b/(2a), where b is equal to 35 and a is equal to -16. We get x=35/32, the x-value of where the vertex lies. You can use this value as the t-value in the previous equation to find the h-value of the vertex. When you do, you get h= 19.1 feet, or answer D.

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6 0
3 years ago
Three salesmen work for the same company, selling the same product. And, although they are all paid on a weekly basis, each sale
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3 0
3 years ago
Read 2 more answers
Solve the blanks <br>thanks
bonufazy [111]
⅔^2+4+6. or ⅔^12

s^(6+1+4)

f question should be f^21 * f^18. and. f^39
5 0
3 years ago
Read 2 more answers
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