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Oksanka [162]
3 years ago
12

WILL MARK BRAINLIEST IF CORRECT! PLS HELP

Mathematics
1 answer:
Elanso [62]3 years ago
4 0

Answer:

y^{\frac{2}{5}}

Step-by-step explanation:

2 - \frac{4}{5} = \frac{2*5}{1*5}-\frac{4}{5}\\\\ = \frac{10}{5}-\frac{4}{5}\\\\= \frac{6}{5}

\frac{a^{m}}{a^{n}}=a^{m-n}\\\\

\sqrt[3]{\frac{y^{2}}{y^{\frac{4}{5}}}} =\sqrt[3]{y^({2-\frac{4}{5})}} \\\\=\sqrt[3]{y^{\frac{6}{5}}}\\\\=(y^{\frac{6}{5}})^{\frac{1}{3}} \\\\=y^{\frac{6}{5}*\frac{1}{3}}\\\\= y^{\frac{2}{5}}

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Answer:

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An art gallery is a 6 story square pyramid with base are 1/2 acre ( 1 acre =n4840 yd, 1 story = 10ft) . Estimate the volume in c
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3 years ago
Ray has found that his new car gets 31 miles per gallon on the highwayand 26 miles per gallon in the city. He recently drove 285
Mkey [24]

Answer:

Highway = 155\ miles

City = 130\ miles

Step-by-step explanation:

Given

Highway = 31mi/gallon

City = 26mi/gallon

Total\ Miles = 285

Total\ Gallons = 10

Required

Determine the number of miles driven on the highway and on the city

Represent the gallons used on highway with h and on city with c.

So, we have:

c + h = 10 ---- gallons used

and

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In the first equation, make c the subject

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Substitute 10 - h for c in the second equation

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Open bracket

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Collect like terms

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c = 5

If on the highway, he travels 31 miles per gallon, then his distance on the highway is:

Highway = 31 * 5

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8 0
3 years ago
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lina2011 [118]
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