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2 years ago

Are 3 6 9 12 15 and 18 a related function

Mathematics

2 answers:

hichkok12 [17]2 years ago

8 0

Yeah bc they all share 3

Ymorist [56]2 years ago

8 0

Yes, they are shared the number 3!

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How can you use the quadratic formula to complete a square?

Marina86 [1]

It has become somewhat fashionable to have students derive the Quadratic Formula themselves; this is done by completing the square for the generic quadratic equation ax2 + bx + c = 0. While I can understand the impulse (showing students how the Formula was invented, and thereby providing a concrete example of the usefulness of abstract symbolic manipulation), the computations involved are often a bit beyond the average student at this point.

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3 years ago

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What is the direction and strength of the association between the variables?

lina2011 [118]

Answer: strong negative

7 0

2 years ago

Ahhhh help everyone help me solve this ....

vovangra [49]

Answer:

$y = \frac{18 {w}^{2} {x}^{2} {z}^{2} }{25}$

Step-by-step explanation:

$\frac{3wx}{ \sqrt{2y} } = \frac{5}{2z} \\ \\ \sqrt{2y} \times 5 = 3wx \times 2z \\ \\ \sqrt{2y} \times 5 = 6wxz \\ \\ \sqrt{2y} = \frac{6wxz}{5} \\ \\ {( \sqrt{2y} })^{2} = {( \frac{6wxz}{5} })^{2} \\ \\ 2y = \frac{36 {w}^{2} {x}^{2} {z}^{2} }{25} \\ \\ \\ y = \frac{36 {w}^{2} {x}^{2} {z}^{2} }{25} \div 2 \\ \\ \\ y = \frac{36 {w}^{2} {x}^{2} {z}^{2} }{25} \times \frac{1}{2} \\ \\ \\ y = \frac{36 {w}^{2} {x}^{2} {z}^{2} }{50} \\ \\ \\ y = \frac{18 {w}^{2} {x}^{2} {z}^{2} }{25}$

I hope I helped you^_^

4 0

2 years ago

20 PTS BRAINLIEST HELPPPPPPP

lesya [120]

Answer:

The answer is D, (-3,3)

Step-by-step explanation:

Multiply K's cooridinates (-2,2) by 3/2. (-2 × 3/2) (2× 3/2)

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3 years ago

F(t)=t^2+19t+60<br> What are the zeros of the function and what is the vertex of the parabola?

SVEN [57.7K]

Answer: $-4,-15;\ \left(-\dfrac{19}{2},-\dfrac{121}{4}\right)$

Step-by-step explanation:

Given

Function is $F(t)=t^2+19+60$

Zeroes of the function are

$t^2+19t+60=0\\\\\Rightarrow t=\dfrac{-19\pm\sqrt{19^2-4\times 1\times 60}}{2\times 1}\\\\\Rightarrow t=\dfrac{-19\pm \sqrt{121}}{2}\\\\\Rightarrow t=\dfrac{-19\pm 11}{2}\\\\\Rightarrow t=-4,-15$

Using completing the square method

$y=t^2+2\times \dfrac{19}{2}t+\dfrac{19^2}{2^2}-\dfrac{19^2}{2^2}+60\\\\y=\left(t+\dfrac{19}{2}\right)^2+60-\dfrac{361}{4}\\\\y=\left(t+\dfrac{19}{2}\right)^2-\dfrac{121}{4}\\\\y+\dfrac{121}{4}=\left(t+\dfrac{19}{2}\right)^2\\\\\left(y-(-\dfrac{121}{4}\right)=\left(t-(-\dfrac{19}{2})\right)^2\\\\\text{The vertex is }\left(-\dfrac{19}{2},-\dfrac{121}{4}\right)$

4 0

2 years ago