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3 years ago

Are 3 6 9 12 15 and 18 a related function

Mathematics

2 answers:

hichkok12 [17]3 years ago

8 0

Yeah bc they all share 3

Ymorist [56]3 years ago

8 0

Yes, they are shared the number 3!

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Find the area of each parallelogram. What is the relationship between the areas?

castortr0y [4]

Answer:

Area of parallelogram is given by:

$A = bh$

where b is the base and h is the height of parallelogram.

In parallelogram TQRS.

Coordinate of TQRS are;

T(8, 16), Q(4, 4), R(16, 4) and S(20, 16)

Coordinate of T'Q'R'S' are;

T'(2, 4), Q'(1, 1), R'(4, 1) and S'(5, 4)

Find the length of QR and PT:

Using distance(D) formula:

$D = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

$QR = \sqrt{(4-16)^2+(4-4)^2} =\sqrt{(-12)^2+0}= \sqrt{144}= 12$ units

Similarly;

For PT:

From the graph:

P(8, 4) and T(8, 16), then

$PT = \sqrt{(8-8)^2+(4-16)^2} =\sqrt{(-0)^2+(-12)^2}= \sqrt{144}= 12$ units

In parallelogram TQRS

PT represents the height and QR represents the base of the parallelogram respectively.

then;

Area of parallelogram TQRS = $QR \cdot PT$

⇒Area of parallelogram TQRS = $12 \cdot 12 = 144$ unit square.

Now, in parallelogram T'Q'R'S'

Q'R' represents the base and P'T' represents the height of the parallelogram respectively.

here, P'(2, 1)

Find the length of Q'R' and P'T':

$Q'R' = \sqrt{(1-4)^2+(1-1)^2} =\sqrt{(-3)^2+0}= \sqrt{9}= 3$ units

$P'T' = \sqrt{(2-2)^2+(1-4)^2} =\sqrt{(-0)^2+(-3)^2}= \sqrt{9}= 3$ units

Then;

Area of parallelogram T'Q'R'S' = $Q'R' \cdot P'T'$

Area of parallelogram T'Q'R'S' = $9 \cdot 9= 81$ unit square.

Now, we have to find the relationship between the areas.

$\frac{\text{Area of parallelogram TQRS}}{\text{Area of parallelogram T'Q'R'S'}} = \frac{144}{81}$

then;

the relationship between the areas of TQRS and T'Q'R'S' is:

$\text{Area of parallelogram TQRS} = \frac{144}{81} \cdot {\text{Area of parallelogram T'Q'R'S'}$

7 0

3 years ago

5 1/3 + (-4 1/6)+ (-2 1/2)

nlexa [21]

Answer:

$-\frac{4}{3}$

Step-by-step explanation:

We are given that

$5\frac{1}{3}+(-4\frac{1}{6})+(-2\frac{1}{2})$

We have to find the value of given expression

$\frac{5(3)+1}{3}-(\frac{4(6)+1}{6})-(\frac{2(2)+1}{2})$

$=\frac{15+1}{3}-\frac{24+1}{6}-\frac{4+1}{2}$

$=\frac{16}{3}-\frac{25}{6}-\frac{5}{2}$

LCM(2,3,6)=6

$=\frac{32-25-15}{6}$

$=\frac{32-40}{6}$

$=\frac{-8}{6}$

$=-\frac{4}{3}$

6 0

3 years ago

We usually Round off the 79.90% to 80.<br> What value does 80 count?

pochemuha

Answer: 00.10

Step-by-step explanation: Add 00.10 to 79.90 and you get 80. Brainliest please?

4 0

3 years ago

Give the coordinates of the point located halfway between (2,1) and (2,4).

nordsb [41]

((X1+x2)/2,(y1+y2)/2) ---> ((2+2)/2,(1+4)/2) ---> (2,2.5)

8 0

3 years ago

The width of a rectangular garden is 23 and a half feet and the perimeter of the garden is 134 feet. Qhat ia the area of the gar

aleksandrvk [35]

Answer:

1022.25 square feet

Step-by-step explanation:

The length and width sum to half the perimeter, so the length is ...

P/2 -W = length = 134/2 -23.5 = 43.5 . . . . feet

The area is the product of length and width, so is ...

A = LW = (43.5 ft)(23.5 ft) = 1022.25 ft^2

The area of the garden is 1022.25 ft^2.

3 0

4 years ago